0  900  908  914  918  924  926  930  936  938  944  950  954  956  960  966  968  974  978  980  984  986  990  992  994  995  996  998  999  1000  1002  1004  1008  1010  1014  1016  1020  1026  1028  1034  1038  1040  1044  1050  1056  1058  1064  1068  1070  1076  1080  1086  1094  3002 

湖北省省实验中学2009届高三年级理科综合能力测试(十)        命题人:黄琼 高晓军 龙信和        时间:150分钟  总分300

I卷(共126分)

以下数据可供解题时参考:相对原子质量(原子量): Mg   24; Al  27

试题详情

本资料来源于《七彩教育网》http://www.7caiedu.cn

《解三角形》

 

试题详情

海南省国兴中学 海师附中 嘉积中学 三亚一中2009年高三联考物理科试卷

注意事项:

1.本试卷分第I卷(选择题)和第II卷(非选择题)两部分。答卷前,请考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答第I卷时,选出小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。如需改动,用橡皮擦干净后,用再选涂其它答案标号。写在本试卷上无效。

3.回答第II卷时,将答案写在答题卡上。写在本试卷上无效。

4.考试结束后,将本试卷和答题卡一并交回。

 

第Ⅰ卷(选择题,共34分)

试题详情

揭阳华侨中学高三物理练习题 2009-05-07

1.下面列举的事例中正确的是(     ).

A.居里夫妇用α粒子轰击铝箔时发现了正电子

B.卢瑟福的原子结构学说成功地解释了氢原子的发光现象

C.麦克斯韦从理论上预言了电磁波的存在,赫兹用实验方法给予证实

D.玻尔建立了量子理论,解释了各种原子发光现象

 

2.氢原子的核外电子从一个轨道跃迁到另一轨道时,可能发生的情况有

A.放出光子,电子动能减少,原子势能增加

B.放出光子,电子动能增加,原子势能减少

C.吸收光子,电子动能减少,原子势能增加

D.吸收光子,电子动能增加,原子势能减少

 

3.如图所示,一验电器与锌板相连,现用一弧光灯照射锌板,关灯后,指针保持一定偏角,下列判断中正确的是

A.用一带负电(带电量较少)的金属小球与锌板接触,则验电器指针偏角将增大

B.用一带负电(带电量较少)的金属小球与锌板接触,则验电器指针偏角将减小

C.使验电器指针回到零后,改用强度更大的弧光灯照射锌板,验电器指针偏角将比原来大

D.使验电器指针回到零后,改用强度更大的红外线灯照射锌板,验电器指针一定偏转

 

4.放在光滑水平面上的物块1、2用轻质弹簧秤相连,如图所示.今对物块1、2分别施以相反的水平力F1 、F2.且F1大于F2,则弹簧秤的示数

A.一定等于F1+F2

B.一定等于F1-F2               

C.一定大于F2小于F1

D.条件不足,无法确定

 

5.如图所示,斜面体P放在水平面上,物体Q放在斜面上.Q受一水平作用力F,Q和P都静止.这时P对Q的静摩擦力和水平面对P的静摩擦力分别为f1、f2.现使力F变大,系统仍静止,则

A. f1、f2都变大           B.f1、f2都不一定变大

C. f1变大,f2不一定变大   D. f2变大,f1不一定变大 

 

6.如图所示,质量为m的木块在质量为M的长木板上向右滑行,木块同时受到向右的拉力F的作用,长木板处于静止状态;已知木块与木板间的动摩擦因数为μ1,木板与地面间的动摩擦因数为μ2,则

A.木板受到地面的摩擦力的大小一定是μ1mg

B.木板受到地面的摩擦力的大小一定是μ2(m十M)g

C.当F>μ2(m+M)g时,木板便会开始运动

D.无论怎样改变F的大小,木板都不可能运动

7.如图所示,在台秤的托盘上放着一个支架,支架上挂着一个电磁铁A,电磁铁的正下方有一铁块B,电磁铁不通电时,台秤示数为G,当接通电路,在铁块被吸起上升的过程中,台秤的示数将                                           

A.不变                                       B.变大

C.变小                                           D.忽大忽小

 

8.如图所示,甲、乙两电路中电源完全相同,电阻R1>R2,在两电路中分别通过相同的电量Q的过程中,下列关于两电路的比较,正确的是

  A.电源内部产生电热较多的是甲电路中的电源

  B.R1上产生的电热比R2上产生的电热多

  C.电源做功较多的是乙电路中的电源

  D.电源输出功率较大的是乙电路中的电源

 

9.如图所示,一个带负电的油滴以初速v0从P点倾斜向上进入水平方向的匀强电场中,若油滴到达最高点时速度大小仍为v0,则油滴最高点的位置在

A.P点的左上方     B.P点的右上方

C.P点的正上方     D.上述情况都可能

 

10.如图所示,在圆形区域内存在一垂直于纸面向里的匀强磁场,一束速率各不相同的质子从A点沿磁场圆形边界的半径方向射入磁场。关于质子在该磁场内运动过程的说法正确的是

A.运动时间越长的,其轨迹越长

B.运动时间越长的,其射出磁场时的速率越大

C.运动时间越长的,其轨迹对应的圆心角越大

D.运动时间越长的,其速度方向的偏转角越大

 

11.如图所示,宽h=2cm的有界匀强磁场,纵向范围足够大,磁感应强度的方向垂直纸面向内,现有一群正粒子从O点以相同的速率沿纸面不同方向进入磁场,若粒子在磁场中做匀速圆周运动的轨道半径均为r=5cm,则

A.右边界:-4cm<y<4cm有粒子射出

B.右边界:y>4cmy<-4cm有粒子射出

C.左边界:y>8cm有粒子射出

D.左边界:0<y<8cm有粒子射出

 

12.如图所示,平行于纸面水平向右的匀强磁场,磁感应强度B1=1T。位于纸面内的细直导线,长L=1m,通有I=1A的恒定电流。当导线与B1成600夹角时,发现其受到的安培力为零。则该区域同时存在的另一匀强磁场的磁感应强度B2大小可能值

A.T      B.T   

C.1 T       D.T

                  

13.(Ⅰ) (10分)某同学设计了一个探究加速度与物体所受合力F及质量m间关系的实验.图(a)为实验装置简图,A为小车,B为打点计时器,C为装有砂的砂桶,D为一端带有定滑轮的长方形木板,实验中认为细绳对小车拉力F等于砂和砂桶总重力,小车运动加速度a可由纸带上点求得.

 

 

 

 

 

 

 

 

 

次   数

1

2

3

4

5

6

7

8

小车加速度a/ms-2

1.90

1.72

1.49

1.25

1.00

0.75

0.50

0.30

小车质量m/kg

0.25

0.29

0.33

0.40

0.50

0.71

1.00

1.67

4.00

3.50

3.00

2.5

2.00

1.40

1.00

0.60

(1)图(b)为某次实验得到的纸带(交流电的频率为50Hz),由图中数据求出小车加速度值为          _________m/s2

 

 

 

 

 

 

 

 

 

 

(2)保持砂和砂桶质量不变,改变小车质量m,分别得到小车加速度a与质量m及对应的数据如表中所示,根据表中数据,为直观反映F不变时a与m的关系,请在方格坐标纸中选择恰当物理量建立坐标系,并作出图线;

从图线中得到F不变时小车加速度a与 质量m间定量关系是_____________;

 

(3)保持小车质量不变,改变砂和砂桶质量,该同学根据实验数据作出了加速度a与合力F图线如图(C),该图线不通过原点,明显超出偶然误差范围,其主要原因是:

                                                                        .

 

 

 

 

 

 

 

 

 

 (Ⅱ)某同学用如图所示的实验装置探究小车动能变化与合外力对它所做功的关系。图中A为小车,连接在小车后面的纸带穿过打点计时器B的限位孔,它们均置于水平放置的一端带有定滑轮的足够长的木板上,C为弹簧测力计,不计绳与滑轮的摩擦。实验时,先接通电源再松开小车,打点计时器在纸带上打下一系列点。

(1)该同学在一条比较理想的纸带上,从点迹清楚的某点开始记为O点,顺次选取5个点,分别测量这5个点到O之间的距离,并计算出它们与O点之间的速度平方差:

 ,填入下表:

未标题-5

为纵坐标,以s为横坐标在方格纸中作 

图象.若测出小车质量为0.2kg,结合图 

象可求得小车所受合外力的大小为      N

(2)若该同学通过计算发现小车所受合外力小于测

学科网(Zxxk.Com)力计读数,明显超出实验误差的正常范围.你认

为主要原因是                           

实验操作中改进的措施是                 

                                           

 

 

 

 

14.在实验室中测量电源的电动势和内电阻,可以提供的器材有:

a)待测电池:电动势E(约3V)、内电阻r(约1Ω)

b)电压表V:量程15V,内电阻

c)电流表A1:量程0.6A,内阻

d)电流表A2:量程1mA,内阻r2=200Ω

e)滑动变阻器R1:阻值0―200Ω,额定电流1.5A

f)滑动变阻器R2:阻值0―20Ω,额定电流1.5A

g)电阻箱R3:9999Ω

以及开关,导线,坐标纸等。

为了尽可能准确地测量待测电池的电动势和内电阻:

①实验所用器材除了待测电池和导线、开关、坐标纸等,还需选择必要的器材有(填器材前的序号)              

②画出测量电池电动势和内电阻的电路图。

③说明测量的主要实验步骤。(要求用图象法处理实验数据。)

 

15.如图,圆环质量为M,经过环心的竖直钢丝AB上套一质量为m的小球,今将小球沿钢丝AB以初速度v0从A点竖直向上抛出,致使环对地面刚好无压力,求:

⑴ 小球上升的加速度。

⑵ 小球能达到的最大高度。(球不会碰到B点)

 

 

16.(16分)如图所示,MN为纸面内一竖直分界线,P、D是纸面内水平方向上的两点。两点之间的距离为L,D点距分界线的距离为,一质量为m、电量为q的带正电粒子在纸面内从P点开始以v0的水平初速度向右运动,经过一段时间后在MN左侧空间加上垂直纸面向里的磁感应强度为B的匀强磁场,磁场维持t0时间后撤除,随后粒子再次通过D点且速度方向竖直向下。粒子的重力不计,求:

  (1) 粒子在加上磁场前运动的时间t.    、

  (2) 满足题设条件的磁感应强度B的最小值及B最小时t0的值.

 

 

试题详情

本资料来源于《七彩教育网》http://www.7caiedu.cn

  《算法初步》

 

试题详情

2009届巢湖市第六中学高三

第六次月考

第一部分  听力(共两节,满分30分)

第一节(共5小题;每小题1.5分,满分7.5分)

       听下面5段对话。每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。

1. Which is the first program the woman is planning to watch?

A. A movie.        B. A cartoon.     C. A football game.

2. What can we learn from this conversation?

A. The wind has stopped but it's still raining.    B. The rain stopped.

C. It's still raining and the wind is blowing.

3. What country does Suzanne presently call her home?

A. America.        B. England.       C. Spain.

4. Where does the conversation take place?

A. In the man's house.    B. In a dinning-room.    C. In a restaurant.

5. What job is the man poking for?

A. He wants to be with the computer center.

B. He wants to work at a computer servicing company.

C. He wants to work in the computer market department.

第二节 (共15小题;每题1.5分,满分22.5分)

听下面5段对话或独白。每段对话或独白后有几个小题,从题中所给的A,B,C三个选项中选出最佳选项,并标在试卷的相应位置。听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,每小题将给出5秒钟的作答时间。每段对话或独白读两遍。

听第6段材料,回答第6―7题。

6. What kind of car does the woman want?

A. A new car.      B. A second-hand car.     C. A cheap car.

7. What happened to the woman's car?

A. It broke down.   B. It was stolen.     C. It was given to her son.

听第7段材料,回答第8―9题。

8. What does David want Julie to do?

A. To tell him her telephone number.   B. To go out with him.   C. To visit him.

9. When will they meet?

A. On Sunday.     B. On Saturday.           C. On Thursday.

听第8段材料,回答第10―12题。

10. Which statement is right?

A. The exam yesterday was harder than the last one.

B. The exam yesterday was shorter than the last one.

C. The exam yesterday was as easy as the last one.

11. Why did Mary make some stupid mistakes?

A. Because he didn’t work hard.    B. Because she didn’t take many courses.

C. Because she was too careless.

12. Who is a better student?

A. Mary.      B. Jimmy.  C. The man.

听第9段材料,回答第13―16题。

13. Who is answering the call?

A. Mary.      B. Jean.     C. Anna

14. Why is Pat making the telephone call?

A. To tell his friend to attend a meeting.

B. To tell his friend to hand in the experiment report.

C. To tell his friend to come to work for the Chemistry Department.

15. Who is Jean?

A. Annals sister-in-law.   B. Mary's sister-in-law.   C. Pat's friend.

16. Which of the following do you think is true?

A. Pat knows Mary.    B. Jean knows Pat.    C. Anna doesn't know Pat.

听第10段材料,回答第17―20题。

17. What is the purpose of the talk?

A. To describe a college training course.   B. To employ people for a job.

C. To talk about problems the airline company faces.

18. According to the speaker, how many people are accepted for the training program every year?     A. About one thousand.   

B. Several thousand.   C. Fewer than one thousand.

19. What subject matter does the speaker mention is included in the training?

A. Psychology.         B. Physical language.  C. Geography.

20. Why does the speaker mention headwaiters?

A. To explain her previous job.

B. To describe the background needed by people asking for the job.

C. To describe some of the skills people working in the plane need.

­

第二部分:知识运用(共两节,满分45分)

第一节:单项填空(每小题1分,满分15分)

从A、B、C、D四个选项中,选出可以填入空白处的最佳选项。

21. ―_______ noise outside!   

―_______. I’ll close the doors and the windows. Now let’s go on.

A. What a; Not at all        B. How; That’s right

C. How; All right           D. What; Never mind

22. The hard-working farmers and their happy life we saw in the countryside________ us very much.

A. frightened          B. impressed            C. disappointed          D. expressed

23. Was it 8 o’clock _______ you heard someone _______ at the door?

A. when; knocking        B. when; knock             C. that; knocking           D. that; knock

24. No computer so far _______ can have the same ability as human brains.

A. be built                    B. having built                     C. being built                D. built

25. _______ Beijing you see today is quite _______ different city from what it used to be.

A. The; 不填               B. The; a                      C. 不填; the                 D. A; a

26. ― It was careless of you _______ your clothes outside all night. 

― My God! ______.

A. to leave; So did I     B. leaving; So do I

C. to have left; So I did D. having left; So do I

27. ― What do you think of the speech?    

― The speaker said _______ nothing worth _______.

A. nearly; listening to   B. hardly; listening

C. scarcely; listening to  D. almost; listening to

28. --I tried to get a hold of Ben last night, but it was so difficult to get through.

--_______. Maybe he was on the Net.

A. That’s probably it    B. That’s strange   C. That’s true D. I know why

29. ― When did he start?     ― He started _______ he got her letter.

A. the moment    B. as long as        C. since        D. until

30. No one would have time to read or listen to an account of everything _______ going on in the world.  

A. it is      B. as is      C. that is   D. what is

31. ― Would you mind _______ me the dictionary? 

― Of course not. But it is ______ my reach.

A. passing; out              B. passing; beyond        C. to pass; far away              D. to pass; out of

32. He was _______ today, but was asked to stay _______ week.

A. to have returned; another   B. returning; one more 

C. returned; another          D. to return; other

33. ―_______ helps others will be helped. 

― So I’ll be thankful to and try to help _______ has helped us.

   A. Whoever; whomever     B. Whoever; whoever 

C. Who; whoever              D. Who; whomever

34. ― Your sister nearly _______ all her spare time to her course during the three years.

   ― That’s right, or she_______ the first place in her school in the 2000 College Entrance Examination.   

A. spent; wouldn’t take    B. devoted; wouldn’t have taken

   C. hadn’t devoted; hadn’t taken  D. hadn’t spent; couldn’t take

35. She’s a teacher, _______ is clear from her manner.

A. that    B. what         C. as       D. who

第二节:完形填空(共20小题;每小题1.5分,满分30分)

阅读下面短文,掌握其大意,然后从短文后所给各题的四个选项(A、B、C和D)中,选出可以填入空白处的最佳选项。

There had been a big battle the day before and our army had taken the enemy's defence works. Night fell and we were in a trench (战壕) ____36____the enemy had dug as the last ____37____of defence. We could ____38____them digging a new trench ____39____in the distance. And by the morning we could see the ____40____of the spades (铲子) as they____41____the earth out.

   In our trench, some soldiers ____42____time shooting at the enemy spades to see ____43____they could hit any of them. Then one of the enemy soldiers ____44____our game. He would put his spade up suddenly and ____45____it there for a few seconds to see whether ____46____of us could hit it and then pull it down quickly. ____47____time he would do it in quite a ____48____place. A____49____of our soldiers shot at it ____50____it came up, but none of them ____51____to have hit it. Then there came a time when the spade ____52____down for much longer than ____53____. We thought that the soldier was ____54____from playing the game by an officer. But just ____55____we thought that we could not see the spade again, it came up once more with a bandage (绷带) tied around it.

36. A. where

B. which

C. since

D. when

37. A. result

B. line

C. moment

D. hope

38. A. watch

B. know

C. hear

D. observe

39. A. themselves

B. ever

C. our enemies

D. our game

40. A. tops

B. colors

C. shapes

D. bottoms

41. A. dug

B. carried   

C. threw

D. stole

42. A. spent

B. wasted  

C. grasped

D. enjoyed

43. A. who

B. if

C. how

D. weather

44. A. attends

B. won

C. joined

D. joined in

45. A. keep

B. kept

C. keeping

D. to keep

46. A. all

B. one

C. none

D. each

47. A. Next

B. Other

C. Last

D. Any

48. A. far

B. strange   

C. different

D. various

49. A. sort

B. kind

C. deal

D. number

50. A. suddenly

B. everywhere

C. only

D. whenever

51. A. honored

B. happened

C. expected

D. seemed

52. A. kept

B. remained

C. taken

D. hid

53. A. always

B. usual

C. the rule

D. their expect

54. A. ordered

B. forced

C. prevented

D. left

55. A. then

B. when

C. a minute

D. now

 

第三部分 阅读理解 (共20小题; 每小题2分, 满分40分)

阅读下列短文, 从每题所给的A、B、C、D 四个选项中选出最佳选项。

A

The George Washington School had been standing for more than 100 years. The school building was in good shape, but behind it was an old basketball court. The court’s blacktop had been broken and was overgrown with weeds. The fence around the court was battered, and parts of it lay on the ground. The basketball hoops were bent and rusted.

One cold day in February, Mr. Garson, a biology teacher, was taking a walk during his lunch break. He passed the old basketball court. “What an ugly sight!” he said, groaning. As he stared at the empty court, he had a vision. He stopped and let the vision take shape in his imagination. In his mind, he pictured something quite different from what he actually saw.

Mr. Garson asked the school board for money to turn his vision into a reality. In April he organized a group of community volunteers to tear up the old basketball court and take it away. Then he persuaded a local farmer to bring truckloads of good topsoil free of charge, which several students spread over the field. A group of parents volunteered to build a new fence around the land. Mr. Garson bought some garden tools. He also bought seeds and young plants. In May students planted tomatoes, potatoes, corn, lettuce, onions, and peppers. In one place they planted a dozen kinds of flowers that would bloom through the summer and fall.

Two students checked the garden and watered it every day. On Saturdays throughout the summer, groups of students gathered to weed (除草) the garden and harvest what was ripe. In September students enjoyed eating fresh produce from the George Washington garden for lunch. Most days there were freshly cut flowers on the breakfast tables. In late fall a local farmer plowed under the garden so that it would be ready for planting again in the spring.

 “What a beautiful sight!” Mr. Garson announced a speech at the first school assembly. “It proves that we can change things if we work together toward a common goal.”

56. The best title of this passage is _______.

A. What a basketball court!   B. How hard the work is!

C. We need vegetables!       D. What a sight!

57. In this selection, the word “battered” means_______.

A. damaged   B. repaired   C. locked    D. high

58. What is one theme expressed in this selection?

A. It takes a lot of hard work to get large donations.

B. It is important to eat a lot of fresh fruits and vegetables.

C. You shouldn’t be discouraged if you don’t succeed right away.

D. One person with a vision can make a big difference.

59. How does Mr. Garson get topsoil for the garden?

A. He buys it.       B. The school board supplies it.

C. A local farmer donates it.  D. He finds it under the basketball court.

 

B

Creativity(创造性)is the key to a brighter future, say education and business experts. Here is how schools and parents can encourage this important skill in children.

    If Dick Drew had listened to his boss in 1925, we might not have a product that we now think or as of great importance: a new type of tape. Drew worked for the Minnesota Mining Company. At work he developed a kind of material strong enough to hold things together. But his boss told him not to think more about the idea. Finally, using his own time, Drew improved the tape, which now is used everywhere by many people. And his former company learned from its mistake. Now it encourages people to spend 15 percent of their work time just thinking about and developing new ideas.

    Creativity is not something one is just born with, nor is it necessarily a character of high intelligence(智力).The fact that a person is highly intelligent does not mean that he uses it creatively. Creativity is the matter of using the resources one has to produce new ideas that are good for something.

Unfortunately, schools have not tried to encourage creativity. With strong attention to test results and the development of reading, writing and mathematical skills, many educators give up creativity for correct answers. The result is that children can give back information but can't recognize ways to use it in new situations. They may know the rules correctly, but they are unable to use them to work out practical problems.

It is important to give children choices. From the earliest age, children should be allowed to make decisions and understand their results. Even if it's choosing between two food items for lunch, decision-making helps thinking skills. As children grow older, parents should let their children decide how to use their time or spend their money, but not tell them too much if they make the wrong decision. The child may have a hard time, but that is all right. This is because the most important character of creative people is a very strong desire to find a way out of trouble.

60.What did the company where Drew once worked learn from its mistake?

  A. They encouraged people to work a longer time.

B. They discouraged people to think freely.

C. They asked people to spend all their work time developing new ideas.

D. They encouraged people to spend some of their work time considering and improving new ideas.

61. Creativity is something_______.

A. that people are born with       B. that depends on intelligence

C. that is a way of using what one has learned to work out new problems

D. that is not important at all

62.Why don't schools try to encourage creativity?

A. They don't understand the importance of education.

B. They don't want their students to think about anything

  C. They pay too much attention to examination marks, language and mathematical skills.

  D. They think it is very important to remember some information.

63.What should the parents do when their children decide how to spend their money?   A. Try to help them as much as possible

B. Take no notice of whatever they do.

  C. Help them if their decision is wrong, but not too much.

D. Leave them as they are.

 

C

Geologists have been studying volcanoes for a long time. Though they have learned a great deal, they still have not discovered the causes of volcanic action. They know that the inside of the earth is very hot, but they are not sure exactly what causes the great heat. Some geologists have thought that the heat is caused by the great pressure of the earth's outer layers(层). Or the heat may be left from the time when the earth was formed. During the last sixty years scientists have learned about radium, uranium (铀), thorium, and other radioactive elements(放射性元素). These give out heat all the time as they change into other elements. Many scientists now believe that much of the heat inside the earth is produced by radioactive elements.

Whatever the cause of the heat may be, we do know that the earth gets hotter the farther down we dig. In deep mines and oil wells the temperature rises about 1ㄈ for each 50 feet. At this rate the temperature 40 miles below the earth's surface would be over 4,000. This is much hotter necessary to melt(融化) rock. However, the pressure of the rock above keeps most materials from melting at their usual melting points. Geologists believe that the rock deep in the earth may be plastic, or puttylike. In other words, the rock yields (屈服) slowly to pressure but is not liquid. But if some change in the earth's crust releases the pressure, the rock melts. Then the hot, liquid rock can move up toward the surface.

 When the melted rock works its way close to the earth's crust, a volcano may be formed. The melted rock often contains steam and other gases under great pressure. If the rock above gives way, the pressure is released.

Then the sudden expansion(膨胀) of the gases causes explosion. These blow the melted rock into pieces of different sizes and shoot them high in the air. Here they cool and harden into volcanic ash. Some of the materials fall around the hole made in the earth's surface. The melted rock may keep on rising and pour out as lava. In this way, volcanic ash and lava build up the mountains that we call volcanoes.

64. The main idea of this passage is the _______.

A. interior (内部) of the earth   B. formation of volcanoes

   C. results of vocalic action      D. work of geologists

65. The cause for the heat in interior of the earth is_______.

A. radioactive elements     B. the great pressure of the earth

C. not determined   D. the heat remaining from the formation of the earth

66. If the temperature at the earth's surface is 20 ㄈ, the temperature in a coal mine 500 feet below the surface would, in degrees, _______.  

A. 30      B. 40        C. l20    D. 500

 

D

In cars of normal design, the petrol system is made up of three parts: storage tanks, a pump and a carburetor(汽化器).

       The petrol tank is fitted at the back of the car where it is out of the way, yet easily filled at a gas station. Tanks are in various capacity but they usually hold enough petrol for 250~300 miles running. Because the tank is at the opposite end of the car from the carburetor, which is fitted high up on the engine, a pump is needed to draw the petrol from one to the other, as it is from the carburetor that the petrol in finally fed into the engine. Pumps can be of two kinds: electrically operated or mechanically driven from the engine.

67. Which of the following pictures shows the correct petrol system described in this passage?

 

 

 

 

 

 

 

 

68. The text offers the reason why _______.

       A. there are different types of tanks in capacity                           

B. the tank is designed at the back of the car

       C. the pump is mechanically driven from the engine  

D. the petrol is fed into the engine from the carburetor

69. It is necessary to use a pump to send petrol to carburetor because _______.

       A. the engine needs supply with a certain amount of petrol           

B. the pump can press the petrol to recycle

       C. the carburettor has difficulty in drawing petrol from the tank   

D. the tank isn’t fitted in proper position

70. According to the text one tube(管道)of the _______.

       A. pump may be joined to the engine directly                             

B. carburetor may be joined to the engine directly                       

C. tank may be joined to the carburetor directly                          

D. engine may be joined to the tank directly

 

E

Altimeter

    An altimeter is an instrument used in an airplane to tell the pilot how high he is flying.

    The altimeter used in most airplanes is a kind of barometer, which, like barometer found in ordinary homes, is a measuring instrument for air pressure. The weight of the atmosphere presses downwards everywhere. At sea level this pressure is more than 14 pounds on every square inch of the surface. The higher you go into the air, the lower the air pressure is. An altimeter measures this air pressure to show the altitude of the airplane, or, how high it is above sea level.

    But the altimeter does not show how high the plane is above the ground. A plane might be flying at an altitude of 15,000 feet, but it would be only a thousand feet or so above the ground if the land in that area happened to be 14,000 feet above sea level.

    The pilot adjusts his altimeter to the actual sea-level pressure before leaving the airport and then corrects it in flight by new information given to him by radio. He flies high enough to be above any mountain he may pass on his course. The barometer altimeter is correct within about 300 feet.

    Another kind of altimeter, the radio altimeter, makes use of radio reflection. It calculates the height of the flying plane by sending out electrical signals to the surface below and measuring the time required for them to bounce back(反弹). It is correct within 15 feet over water, but is not reliable over land. Big planes usually have both kinds of altimeter.

71. Which of the following diagrams gives the correct relationship between altimeters and barometers? (a--altimeters, b--barometers)

       

72. The following drawing shows a plane flying over a mountain. Which of the heights given in the drawing is given by the barometer altimeter in the plane at this moment?

         

73. The barometer altimeter won’t work if the plane flies______.

A. beyond the atmosphere.        B. above very high land.

C. over very uneven (不平的) ground.   

D. within 1,000 feet of the ground.

74. Suppose a plane using a radio altimeter is flying 10, 000 meters above highland which is 4, 000 meters above sea level. What reading will be given by the altimeter?

    A. 10, 000 meters.               B. 4, 000 meters.  

C. 14, 000 meters.               D. 6, 000 meters

75.Suppose a plane using both kinds of altimeters is flying over a mountainous area where the land rises and falls very abruptly(迅速地). The pilot keeps his plane steady(稳定地)at the same height. What kind of reading will you get on each of the altimeters?    

A. The readings on both altimeters will remain steady. 

   B. The readings on both altimeters will rise and fall abruptly.    

C. The readings on the barometer altimeter will rise and fall abruptly, while that on the radio  altimeter will remain steady.

   D. The readings on the radio altimeter will rise and fall abruptly, while that on the barometer altimeter will remain steady.

第二卷 (共35分)

第四部分  写 作(共两节,满分35分)

第一节:任务型读写(共10小题,每小题1分,满分10分)

阅读下列短文,根据所读内容在文章后的表格中填入恰当的单词。注意:表格中的每个空格只填1个单词。

Speaking in public is most people’s least favorite thing. The reason is that we are all afraid of making fools of ourselves. The more important the speech is, the more frightened we become.

But stop biting your finger-nails. Public speaking is easy. It’s just plain talking, and you talk all the time. Although I’m basically shy (honest!), I’ve been making speeches and talking on radio and television for more than 30 years, and I can tell you that public speaking is not a “gift” like musical talent. Anybody who can talk can speak in public. Here are some of the lessons I have learned: 

   Your audience is going to come away with one or two of your main ideas. One or two. Not ten or 20. If you can’t express in a sentence or two what you intend to get across, then your speech is not focused well enough. And if you don’t have a clear idea of what you want to say, there’s no way your audience will.

  No matter how long or short your speech is, you’ve got to get your ducks in a row―how you are going to open, what major points you want to make and how you’re going to close.

When I do a radio or TV piece, I often write the last sentence first. When you know where you’re headed, you can choose any route to get there. A strong close is critical: the last thing you say is what your audience will most likely remember.

The standard length of a vaudeville act is usually 12 minutes. If all those performers singing and dancing their hearts out couldn’t go on longer without boring the audience, what makes you think you can?

第二节:书面表达(25分):

第二节 书面表达( 满分25分)

近年来,一些西方节日在中国越来越流行。这种现象在网上引起热议。请根据下图描述中国人过洋节的情况,谈谈你对这种社会现象的看法,并将你写的东西在该英语论坛上发表。

要求:1. 表达连贯,逻辑正确。2. 字数150 参考词汇:情人节:Valentine’s Day

 

Title: How to make a (76)________ speech

Techniques

Reasons

Requirements

 

Keep it simple

You should (77)________ your idea well enough

Prepare one or two of your main ideas.

The audience will not catch your idea if your idea is (78)________.

Get (79)________

You should get your speech well organized.

Know very well about the (81)________, body and ending of the speech

If you don’t, the (80)________ will be confused.

 

Keep it (82)________

Your speech should be short enough to hold your audience curiosity and (83)________.

Make your speech as short as (84)________.

If you don’t, the audience will be (85)________.

 

 

 

 

 

 

 

第一部分 听力:(共20题;每题1.5分;共30分)

1-5 ___  ___  ___  ___  ___       6-10___  ___  ___  ___  ___

11-15___  ___  ___  ___  ___     16-20 ___  ___  ___  ___  ___                      

 

第二部分英语知识运用:          

I单项选择:

21-25___  ___  ___  ___  ___    26-30___  ___  ___  ___  ___

31-35___  ___  ___  ___  ___

 

II完型填空:(共20小题;每小题1.5分,满分30分)

36-40___  ___  ___  ___  ___    41-45___  ___  ___  ___  ___

46-50___  ___  ___  ___  ___    51-55 ___  ___  ___  ___  ___                    

 

第三部分 阅读理解:(共20小题;每小题2分,满分40分)

56-60___  ___  ___  ___  ___   61-65___  ___  ___  ___  ___

66-70___  ___  ___  ___  ___   71-75___  ___  ___  ___  ___

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

试题详情

本资料来源于《七彩教育网》http://www.7caiedu.cn

《数系的扩充与复数的引入》

 

试题详情

2009最新全国各地高考模拟题计算题(考前每日两题)汇编

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月12日

1.(16分)长兴是我国最大的蓄电池基地之一,蓄电池是电动自行车的核心部件之一,近几年来电动自行车在长兴城乡十分普及,极大的方便了居民的出行。下表是一辆电动自行车的部分技术指标,其中额定车速是指电动车满载情况下在平直道路上以额定功率匀速行驶的速度。

额定

车速

车质量

载重

电源

电源输

出电压

充电

时间

额定输出

功率

电动机额定工作电压和电流

18 km/h

40 kg

80 kg

36 V/12 AH

≥36 V

6~8 h

180 W

36 V/6A

请参考表中数据,完成下列问题(g取10 m/s2)。

(1)此车所配电动机的内阻是多少?

(2)在行驶过程中电动车受阻力是车重(包括载重)的K倍,试计算K的大小。

(3)若电动车满载时以额定功率行驶,当车速为3 m/s时,加速度为多大?

解:考察电动车在满载且以额定功率匀速行驶时的情形

(1)P=UI=36×6 W=216 W (2分)

P=180 W,所以P=P-P=36 W (2分)

又P=I2r (1分), 所以r==1 Ω. (1分)

(2)P=Fv (1分) f=kmg (1分)

F=f (1分), 即P=kmgv,故k=0.03. (3分)

(3)由牛顿第二定律可知:a= (2分), 即a=0.2 m/s2. (2分)

2.(20分)如图所示(a),M、N为中心开有小孔的平行板电容器的两极,相距D=1 m,其右侧为垂直纸面向里的匀强磁场,磁感强度B=1×103 T,磁场区域足够长,宽为d=0.01 m;在极板M、N之间加有如图(b)所示的变电压(设N极电势高于M极时电压为正)。现有带负电粒子不断从极板M中央小孔处射入电容器内(粒子的初速度可看做为零,重力不计),取其荷质比=2×1011 C/kg,问:

(1)在变交电压第一个周期内哪些时刻进入电容器内的粒子能从磁场的右侧射出来?

(2)若上述交变电压的周期可以变化,则其周期满足什么条件时,才能保证有带电粒从右侧射出来?

解:(1)粒子要从磁场的右侧射出,它做圆周运动的半径须满足

r≥d。(2分)

又r= (3分)

得v> (1分)

粒子在电场中,无论做加速运动还是做减速运动,其加速度都为:

a=? (2分)

设带电粒子先做加速运动后做减速运动至极板N在中央小孔处,以速度v进入磁场中,则:

D=+ (4分)

式中t为粒子做加速运动的时间,得:

t= 2分

代人数据得:t≥0.61×106 s (2分)

所以在0~0.39×106s时间内进入电容器内的粒子将从磁场右侧射出。 (1分)

(2)由以上分析可知,带电粒子加速运动的时间至少为0.61×106 s,则

≥0.61×106 s (2分)

即T≥1.22×106 s。(1分)

 

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月13日

3.(16分)如图所示,AB为竖直墙壁,空间存在着竖直向下的匀强电磁。现将一质量为m的带正电小球在距墙为l的P点以水平速度v向右抛出,球打在墙上的C点。现撤去电场,使球在距墙为2l的Q点仍以水平速度v向右抛出(P、Q在同一水平线上),结果球仍打在墙上的C点。由此可知,小球所受的电场力是重力的多少倍?

 

4. (18分) 如图所示,半径为r的闭合圆环由质量为m、电阻为R的细金属丝制成,圆环水平放置在两磁极的狭缝间,辐向分布的磁场仅存在于圆筒形磁极S和圆柱形磁极N之间,圆环平面与磁场方向平行,圆环所在处的磁感应强度大小为B。圆环从静止开始释放(不计空气阻力),其平面在下落过程中始终保持水平。

    (1)求圆环下落的最大速度vm(设磁场区域在竖直方向足够长);

    (2)当圆环下落的加速度为g/2时,求圆环的发热功率P;

    (3)已知圆环下落时间为T时,下落高度为H,其速度为v0(v0<vm=。若在该时间T内,圆环内产生的热量与一恒定电流I0在该圆环内产生的热量相同,求恒定电流I0的表达式。

         

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月14日

 

 

5.(20分) 如图所示,倾角θ=30°的光滑斜面的底端固定着一个垂直于斜面的挡板,斜面上有一根劲度系数为k=100N/m的轻质弹簧,其两端分别焊接着质量为mB=mC=4kg的B、C两个小球,B球处于静止状态且弹簧压缩量为x。今另有一质量为mA= 1kg的A球从距B球2x的D 点以初速度v0=m/s 沿斜面滑下, A、B两球碰撞后,A球沿斜面向上运动且恰好能回到D点,此时取走A球。(g=10m/s2)求:

    (1) B球静止时弹簧的压缩量x;

    (2) A球下滑2x即将与B球碰撞时的速度v1的大小;

(3) 试推算C球能否被拉离挡板。

6、(16分)如图所示,以O为原点建立直角坐标系Oxy,绝缘光滑水平面沿着x轴,y轴在竖直方向。在水平面上方存在与x轴平行的匀强电场。一个质量m = 2.0×10-3kg、电量q = 2.0×10-6C的带正电的物体(可作为质点),从O点开始以一定的初速度沿着x轴正方向做直线运动,其位移随时间的变化规律为x = 6.0 t -10 t 2,式中x的单位为m,t的单位为s。不计空气阻力,取g =10m/s2

(1)求匀强电场的场强大小和方向;

(2)求带电物体在0.5s内经过的路程;

(3)若在第0.6s末突然将匀强电场的方向变为沿

y轴正方向,场强大小保持不变。求在0~0.8s

内带电物体电势能的变化量。

解:(1)(4分)加速度大小  a = 20m/s2             (1分)

            根据牛顿第二定律  Eq = ma         (1分)

            解得场强    E = 2.0×104N/C         (1分)

                        方向沿x轴负方向      (1分)

(2)(6分)物体在O点的初速度    v0 = 6.0m/s   (1分)    

减速时间    t1 =  = 0.3s          (1分)

0.3s内经过的路程  x1 = = 0.9 m  (1分)

            后0.2s物体做匀加速直线运动,经过的路程

                                x2 = = 0.4m     (1分)

0.5s内物体经过的路程   s = x1+x2 = 1.3m    (2分)

(3)(6分)第0.6s末带电物体回到坐标原点O          (1分)

之后的0.2s物体以初速度v0做类平抛运动

            在y方向根据牛顿第二定律

                  Eq ? mg = ma′  (1分)

                        (1分)

             解得物体在y方向经过的距离y0 = 0.2m  (1分)

             电场力做功  W = Eq y0 = 8.0×10-3J      (1分)

             所以电势能减少8.0×10-3J            (1分)

             (或电势能的变化量为 ∆EP = ? 8.0×10-3J)

 

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月14日

 

 

(1)人从斜坡上滑下的加速度为多大?

(2)若AB的长度为25m,人滑到B处时速度为多大?

(3)若AB的长度为25m,求BC的长度为多少?

解:(1)设人斜坡上滑下的加速度为,由牛顿第二定律有

                                      ①(1分)

                                                                         ②(1分)

                                                                                    ③(1分)

    联立①②③式得                                 ④(1分)

    代入数据得                                                        (2分)

   (2)人滑到B点时                            ⑤(3分)

   (3)在水平轨道上运动时                                        ⑥(1分)

                                                     ⑦(1分)

联立⑥⑦式得                                                    ⑧(2分)

                                      ⑨(2分)

联立⑤⑧⑨式得                            (1分)

8.(18分)如图12所示,竖直平面xOy内存在水平向右的匀强电场,场强大小E=10N/c,在y≥0的区域内还存在垂直于坐标平面向里的匀强磁场,磁感应强度大小B=0.5T。一带电量q=+0.2C、质量m=0.4kg的小球由长L=0.4m的细线悬挂于P点小球可视为质点,现将小球拉至水平位置A无初速度释放,小球运动到悬点P正下方的坐标原点O时,悬线突然断裂,此后小球又恰好能通过O点正下方的N点。(g=10m/s222),求:

(1)小球运动到O点时的速度大小;

(2)悬线断裂前瞬间拉力的大小;

(3)ON间的距离。

 

解:(1)小球从A运到O的过程中,根据动能定理:

                                                                                      ①(3分)

则得小球在O点速度为:

                                                    ②(3分)

(2)小球运动到O点悬线断裂前瞬间,对小球运用牛顿第二定律:

                                                                 ③(2分)

                                                                              ④(1分)

由③④得:                              ⑤(3分)

(3)悬线断后,小球水平方向加速度

                                                             ⑥(2分)

小球从O点运动至N点所用时间

                                                                        ⑦(2分)

ON间距离

                     ⑧(2分)

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月16日

 

 

 

文本框:  9.(20分)如图13甲所示,一边长L=2.5m、质量m=0.5kg的正方形金属线框,放在光滑绝缘的水平面上,整个装置放在方向竖直向上、磁感应强度B=0.8T的匀强磁场中,它的一边与磁场的边界MN重合。在水平力F作用下由静止开始向左运动,经过5s线框被拉出磁场。测得金属线框中的电流随时间变化的图像如乙图所示,在金属线框被拉出的过程中。

(1)求通过线框导线截面的电量及线框的电阻;

(2)写出水平力F随时间变化的表达式;

(3)已知在这5s内力F做功1.92J,那么在此过程中,线框产生的焦耳热是多少?

解:(1)根据                                                   (3分)

又根据                                                    (3分)

    得                                                                              (4分)

(2)由电流图像可知,感应电流随时间变化的规律:I=0.1t    (2分)

由感应电流可得金属框的速度随时间也是线性变化的,

                                                                       (3分)

线框做匀加速直线运动,加速度                        (1分)

线框在外力F和安培力FA作用下做匀加速直线运动,

F-FA=ma                                                                                 (1分)

得力F=(0.2t+0.1)N

(3)t=5s时,线框从磁场中拉出时的速度v5=at=1m/s  (2分)

线框中产生的焦耳热  (2分)

高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。10.(15分)如图8所示,在光滑绝缘的水平桌面上放有四分之一圆弧槽AB,其中虚线OA、OB为圆弧槽的两条半径。沿水平方向有匀强电场,电场方向与OB平行。有一质量为m、电荷量为q的小球,以初速度高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。沿OA方向从O点出发,经过一段时间第一次碰到圆弧槽,碰撞点恰好在圆弧槽AB的中点C处,求:A、B两点间的电势差?

解:带电小球在电场中做类平抛运动,设圆弧半径为R。

据题意:

Rsin45°= v0t                                                                                                         (3分)

Rcos45°=  at2                                                                       (3分)

其中a =                                                                               (3分)

在匀强电场中:E =                                                          (3分)

上式联立解得:UAB =                                             (3分)

(其它解法只要合理同样得分)

 

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月17日

 

高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。

 

11.(18分)有一颗地球卫星,绕地球做匀速圆周运动

卫星与地心的距离为地球半径高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。的2倍,卫星圆

形轨道平面与地球赤道平面重合。卫星上的太阳能

收集板可以把光能转化为电能,太阳能收集板的面

积为高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。,在阳光下照射下每单位面积提供的最大电

功率为高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。。已知地球表面重力加速度为高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。,近似认

为太阳光是平行光,试估算太阳能收集板在卫星绕

地球一周的时间内最多转化的电能?

解:地球卫星做匀速圆周运动,根据牛顿第二定律:

高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。= m(2R0)                                                                               (4分)

在地球表面有: = m′g                                                                       (4分)

∴卫星做匀速圆周运动的周期为:

T = 4π                                                                                             (2分)

如图,当卫星在阴影区时不能接受阳光,据几何关系:

∠AOB = ∠COD =                                           (2分)

∴卫星绕地球一周,太阳能收集板工作时间为:

t =  T                                                                                     (2分)

最多转化的电能:

E = PSt =                                                                              (4分)

高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。12.(21分)如图10所示,匀强磁场区下边界是水平地面,上边界与地面平行,相距高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。=1.0m,两个正方形金属线框高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。在同一竖直平面内,与磁场方向始终垂直。高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。的下边框与地面接触,上边框与绝缘轻线相连,轻线另一端跨过两个定滑轮连着线框高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。。同时静止释放高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。,发现高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。全部离开磁场时,高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。还未进入磁场,而且当线框P整体经过磁场区上边界时,一直匀速运动,当线框Q整体经过磁场区上边界时,也一直匀速运动。若线框P的质量高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。、边长高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。、总电阻高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。,线框Q的质量高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。、边长高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。、总电阻高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。忽略一切摩擦和空气阻力,重力加速度高考资源网( www.ks5u.com),中国最大的高考网站,您身边的高考专家。。求:

   (1)磁感应强度的大小?

   (2)上升过程中线框P增加的机械能的最大值?

解:(1)线框P在磁场中,P上升,Q下落,二者机械能守恒:

(m2-m1)g(h-L1)= 12(m1+m2)v12                                                   (3分)

线框P经过磁场区上边界时:m2g = m1g+                                      (3分)

解得:B =  T≈ 3.33T         v1 = 2m/s                                                               (3分)

(2)从线框P完全离开磁场到线框Q开始进入磁场,二者机械能守恒:

(m2-m1)g(H-h)= (m1+m2)v22-(m1+m2)v12                       (3分)

线框Q经过磁场区上边界时:m2g = m1g+                                      (3分)

解得:H = 1.5m           v2 = 3m/s

线框Q完全进入磁场后到落地前,二者机械能守恒:

(m2-m1)g(h-L2)= (m1+m2)v32-(m1+m2)v22                      (3分)

解得:v3 = 4m/s

线框P增加的机械能ΔE = 12m1v32+m1g(H+h)= 3.3J                                      (3分)

2009最新全国各地高考模拟题计算题(考前每日两题)汇编(05月18日

 

 

 

13.(16分)如图甲所示,一质量为2.0kg的物体静止在水平面上,物体与水平面间的动摩擦因数为0.20。从t=0时刻起,物体受到水平方向的力F的作用而开始运动,8s内F随时间t变化的规律如图乙所示。求:(g取10m/s2

   (1)4s末物体速度的大小;

   (2)在图丙的坐标系中画出物体在8s内的v ? t 图象;(要求计算出相应数值)

 

 

 

 

 

 

 

 

 

解:(1)(6分)物体受到水平力F和摩擦力的作用

设加速度为,4s末速度为,由牛顿第二定律

          (2分)

          (2分)

          (2分)

   (2)(6分)由图知,在4―85s内,物体受到水平力F的大小不变,

       方向改变,设加速度为,5s末速度为

      

           (1分)

          (1分)

       由图知,5―8s内物体只受摩擦力作用,设加速度为,速度为

      

           (1分)

      

       在t=7.5s时物体停止运动,   (1分)

       物体运动的v-t图像如图所示        (2分)

   (3)(4分)由v-t图可知(或计算得出)

       0―4s内   (1分)

       4―5s内   (1分)

       水平力F做功   (1分)

       得    (1分)

 

 

 

 

14.

金属框垂直轨道的边长,两磁场的宽度均与

金属框的边长相同,金属框整个回路的电阻

,g取10m/s2。假如主凤计要求电梯以

的速度匀速上升,求:

   (1)金属框中感应电流的大小及图示时刻感应电流的方向;

   (2)磁场向上运动速度

 

 

试题详情

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网