已知多面体ABCDE中,AB⊥平面ACD,DE⊥平面ACD, AC = AD = CD = DE = 2a,AB = a,F为CD的中点.
(Ⅰ)求证:AF⊥平面CDE;
(Ⅱ)求异面直线AC,BE所成角余弦值;
(Ⅲ)求面ACD和面BCE所成二面角的大小.