函数f(x)满足f(-1)=
,对于x,y∈R,有4f(
)f(
)=f(x)+f(y),则f(-2013)=( )
| 1 |
| 4 |
| x+y |
| 2 |
| x-y |
| 2 |
A、-
| ||
B、
| ||
C、-
| ||
D、
|
已知函数f(x)=1+x-
+
-
+…+
,设F(x)=f(x+3),且函数F(x)的零点均在区间[a,b](a<b,a,b∈Z)内,当b-a取得最小值时,a+b的值为( )
| x2 |
| 2 |
| x3 |
| 3 |
| x4 |
| 4 |
| x2011 |
| 2011 |
| A、-1 | B、-4 | C、-7 | D、-3 |