18.正数5的算术平方根是( )
| A. | ±$\sqrt{5}$ | B. | ±$\frac{5}{2}$ | C. | $\sqrt{5}$ | D. | -$\sqrt{5}$ |
17.下列方程是一元一次方程的是( )
| A. | x-2=3 | B. | 1+5=6 | C. | x2+x=1 | D. | x-3y=0 |
15.
如图,O是直线BC上的 点,OM平分∠AOB,ON平分∠AOC,点E在OM上,过点E作EG⊥OA于点G,EP⊥OB于点P,延长EG,交ON于点F,过点F作FQ⊥OC于点Q,若EF=10,则FQ+EP的长度为( )
| A. | 5 | B. | 10 | C. | 15 | D. | 20 |
14.
已知△ABC如图1所示,平平通过作图得到如图2所示的△A′B′C,其作图步骤为:
①画B′C′=BC;
②分别以点B′C′为圆心,线段AB,AC长为半径画弧,两弧交于点A′;
③连接A′B′,A′C′,则判断△ABC≌△A′B′C′的依据是( )
0 293225 293233 293239 293243 293249 293251 293255 293261 293263 293269 293275 293279 293281 293285 293291 293293 293299 293303 293305 293309 293311 293315 293317 293319 293320 293321 293323 293324 293325 293327 293329 293333 293335 293339 293341 293345 293351 293353 293359 293363 293365 293369 293375 293381 293383 293389 293393 293395 293401 293405 293411 293419 366461
①画B′C′=BC;
②分别以点B′C′为圆心,线段AB,AC长为半径画弧,两弧交于点A′;
③连接A′B′,A′C′,则判断△ABC≌△A′B′C′的依据是( )
| A. | SSS | B. | SAS | C. | ASA | D. | AAS |