18.
如图,在Rt△ABC中,∠C=90°,AC=4,BC=3,点D是AC的中点,连接BD,按以下步骤作图:
①分别以B,D为圆心,大于$\frac{1}{2}$BD的长为半径作弧,两弧相交于点P和点Q;②作直线PQ交AB于点E,交BC于点F,则BF=( )
①分别以B,D为圆心,大于$\frac{1}{2}$BD的长为半径作弧,两弧相交于点P和点Q;②作直线PQ交AB于点E,交BC于点F,则BF=( )
| A. | $\frac{5}{6}$ | B. | 1 | C. | $\frac{13}{6}$ | D. | $\frac{5}{2}$ |
17.
如图,已知点C为线段AB的中点,CD⊥AB且CD=AB=4,连接AD,BE⊥AB,AE是∠DAB的平分线,与DC相交于点F,EH⊥DC于点G,交AD于点H,则HG的长为3-$\sqrt{5}$.
12.
如图,已知△ABC,∠C=90°,按以下步骤:①分别以A、B为圆心,以大于$\frac{1}{2}AB$的长为半径作弧,两弧相交于两点M、N;②作直线MN交BC于点D.若AC=1.5,∠B=15°.则BD等于( )
0 286687 286695 286701 286705 286711 286713 286717 286723 286725 286731 286737 286741 286743 286747 286753 286755 286761 286765 286767 286771 286773 286777 286779 286781 286782 286783 286785 286786 286787 286789 286791 286795 286797 286801 286803 286807 286813 286815 286821 286825 286827 286831 286837 286843 286845 286851 286855 286857 286863 286867 286873 286881 366461
| A. | 1.5 | B. | 2 | C. | 2.5 | D. | 3 |