5.二次函数y=-(x+2)2+1的顶点坐标是( )
| A. | (-2,-1) | B. | (-2,1) | C. | (2,-1) | D. | (2,1) |
4.
如图,在△ABC中,点D在BC上,且BD=2CD,AB⊥AD,若tanB=$\frac{4}{3}$,则tan∠CAD=( )
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| A. | $\frac{\sqrt{3}}{3}$ | B. | $\frac{1}{4}$ | C. | $\sqrt{3}$ | D. | $\frac{1}{3}$ |