题目内容
已知f(x)=
+log2
,则f
+f
+…+f
的值为( )
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515597498.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515612389.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515612726.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515628735.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515644785.png)
A.1 | B.2 | C.2 013 | D.2 014 |
A
对任意0<x<1,可得f(x)+f(1-x)=
.
设S=f
+f
+…+f![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515644785.png)
则S=f
+f
+…+f![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515612726.png)
于是2S=
+
+…+
=
×2 013=2,所以S=1.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515659530.png)
设S=f
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515612726.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515628735.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515644785.png)
则S=f
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515644785.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515722761.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515612726.png)
于是2S=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240505157681273.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240505157841249.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240505158001292.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824050515659530.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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题目内容
A.1 | B.2 | C.2 013 | D.2 014 |