题目内容
若数列{an}满足a1=1,an+1=2an+1(n∈N+),则a10=( )
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试题答案
B
相关题目
已知数列{an}满足a1=1,an+1=2an+1(n∈N*).
(Ⅰ)求证:数列{an+1}为等比数列,并求数列{an}的通项公式;
(Ⅱ)若数列{cn}的通项公式为cn=2n,求数列{an•cn}的前n项和Sn;
(Ⅲ)若数列{bn}满足4b1-14b2-1…4bn-1=(an+1)bn(n∈N*),且b2=4.证明:数列{bn}是等差数列,并求出其通项公式.
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(Ⅰ)求证:数列{an+1}为等比数列,并求数列{an}的通项公式;
(Ⅱ)若数列{cn}的通项公式为cn=2n,求数列{an•cn}的前n项和Sn;
(Ⅲ)若数列{bn}满足4b1-14b2-1…4bn-1=(an+1)bn(n∈N*),且b2=4.证明:数列{bn}是等差数列,并求出其通项公式.
已知数列{an}满足a1=1,an+1=2an+1(n∈N*)
(1)求数列{an}的通项公式;
(2)若数列{bn}满足4b1-14b2-14b3-1…4bn-1=(an+1)bn,证明:{bn}是等差数列;
(3)证明:
+
+…+
<
(n∈N*).
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(1)求数列{an}的通项公式;
(2)若数列{bn}满足4b1-14b2-14b3-1…4bn-1=(an+1)bn,证明:{bn}是等差数列;
(3)证明:
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| a3 |
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| an+1 |
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