摘要:6.数列{an}是等差数列.其前n项和为Sn.若平面上的三个不共线的向量满足且A.B.C三点共线.则S2008= .
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设{an}是等差数列,其前n项和为Sn,已知S7=63,a4+a5+a6=33,
(1)写出数列{an}的通项公式;
(2) 求数列bn=2an+n,求数列{bn}的前n项和Tn;
(3) 求证:
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+
+…+
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(1)写出数列{an}的通项公式;
(2) 求数列bn=2an+n,求数列{bn}的前n项和Tn;
(3) 求证:
| 1 |
| S1 |
| 1 |
| S2 |
| 1 |
| S3 |
| 1 |
| Sn |
| 3 |
| 4 |
设{an}是等差数列,其前n项和为Sn,已知S7=63,a4+a5+a6=33,
(1)写出数列{an}的通项公式;
(2) 求数列bn=2an+n,求数列{bn}的前n项和Tn;
(3) 求证:
+
+
+…+
<
查看习题详情和答案>>
(1)写出数列{an}的通项公式;
(2) 求数列bn=2an+n,求数列{bn}的前n项和Tn;
(3) 求证:
| 1 |
| S1 |
| 1 |
| S2 |
| 1 |
| S3 |
| 1 |
| Sn |
| 3 |
| 4 |
设{an}是等差数列,其前n项和为Sn,已知S7=63,a4+a5+a6=33,
(1)写出数列{an}的通项公式;
(2) 求数列bn=2an+n,求数列{bn}的前n项和Tn;
(3) 求证:
+
+
+…+
<
查看习题详情和答案>>
(1)写出数列{an}的通项公式;
(2) 求数列bn=2an+n,求数列{bn}的前n项和Tn;
(3) 求证:
查看习题详情和答案>>