ÌâÄ¿ÄÚÈÝ

11£®ÀíÂÛ·ÖÎö¿ÉµÃ³öµ¯»ÉµÄµ¯ÐÔÊÆÄܹ«Ê½EP=$\frac{1}{2}$kx2 £¨Ê½ÖÐkΪµ¯»ÉµÄ¾¢¶ÈϵÊý£¬xΪµ¯»É³¤¶ÈµÄ±ä»¯Á¿£©£®ÎªÑéÖ¤ÕâÒ»½áÂÛ£¬A¡¢BÁ½Î»Í¬Ñ§Éè¼ÆÁËÒÔϵÄʵÑ飺¢ÙÁ½Î»Í¬Ñ§Ê×Ïȶ¼½øÐÐÁËÈçͼ¼×ËùʾµÄʵÑ飺½«Ò»¸ùÇáÖʵ¯»ÉÊúÖ±¹ÒÆð£¬ÔÚµ¯»ÉµÄÁíÒ»¶Ë¹ÒÉÏÒ»¸öÒÑÖªÖÊÁ¿ÎªmµÄСÌúÇò£¬Îȶ¨ºó²âµÃµ¯»ÉÉ쳤d£®

¢ÚAͬѧÍê³É²½Öè¢Ùºó£¬½Ó׎øÐÐÁËÈçͼÒÒµÄʵÑ飺½«Õâ¸ùµ¯»ÉÊúÖ±µØ¹Ì¶¨ÔÚˮƽ×ÀÃæÉÏ£¬²¢°ÑСÌúÇò·ÅÔÚµ¯»ÉÉÏ£¬È»ºóÊúÖ±µØÌ×ÉÏÒ»¸ù´øÓвåÏú¿×µÄ³¤Í¸Ã÷ËÜÁϹܣ®ÀûÓòåÏúѹËõµ¯»É£®°Îµô²åÏúʱ£¬µ¯»É¶ÔСÇò×ö¹¦£¬Ê¹Ð¡Çòµ¯Æð£¬²âµÃµ¯»ÉµÄѹËõÁ¿ºÍСÌúÇòÉÏÉýµÄ×î´ó¸ß¶ÈH£®
¢ÛBͬѧÍê³É²½Öè¢Ùºó£¬½Ó׎øÐÐÁËÈçͼ±ûµÄʵÑ飺½«Õâ¸ùµ¯»É·ÅÔÚˮƽ×ÀÃæÉÏ£¬Ò»¶Ë¹Ì¶¨ÔÚÊúÖ±µÄǽÉÏ£¬ÁíÒ»¶Ë±»Ð¡ÌúÇòѹËõ£¬²âµÃѹËõÁ¿Îªx£¬Êͷŵ¯»Éºó£¬Ð¡ÌúÇò´Ó¸ßΪhµÄ×ÀÃæÉÏˮƽÅ׳ö£¬Å׳öµÄˮƽ¾àÀëΪL£®
£¨1£©A¡¢BÁ½Î»Í¬Ñ§½øÐÐÈçͼ¼×ËùʾµÄʵÑéÄ¿µÄÊÇΪÁËÈ·¶¨Ê²Ã´ÎïÀíÁ¿£¿È·¶¨µ¯»ÉµÄ¾¢¶ÈϵÊý£¬ÇëÓÃm¡¢d¡¢g±íʾËùÇóµÄÎïÀíÁ¿$\frac{mg}{d}$£®
£¨2£©Èç¹ûEP=$\frac{1}{2}$kx2 ³ÉÁ¢£¬ÄÇôAͬѧ²â³öµÄÎïÀíÁ¿xÓëd¡¢HµÄ¹ØÏµÊ½ÊÇ£ºx=$\sqrt{2dH}$£¬Bͬѧ²â³öµÄÎïÀíÁ¿xÓëd¡¢h¡¢LµÄ¹ØÏµÊ½ÊÇ£ºx=L$\sqrt{\frac{d}{2h}}$£®
£¨3£©ÊÔ·Ö±ð·ÖÎöA¡¢BÁ½Î»Í¬Ñ§ÖУ¬ÆäÖÐһλͬѧµÄʵÑéÎó²îµÄÖ÷ÒªÀ´Ô´AͬѧʵÑéʱ£¬²»Ò×¾«È·È·¶¨Ð¡ÇòÉÏÉýµÄ×î´ó¸ß¶È£¬
¶øÇÒСÇòÉÏÉýʱÓпÉÄÜÓëËÜÁϹÜÄÚ±Ú½Ó´¥£¬²úÉúĦ²Á´Ó¶ø´øÀ´ÊµÑéÎó²î£®
BͬѧʵÑéʱ£¬Ð¡ÌúÇòÓë×ÀÃæÖ®¼äµÄĦ²Á»á¸øÊµÑé´øÀ´Îó²î£®

·ÖÎö £¨1£©¸ù¾ÝÖØÁ¦Ó뵯»ÉµÄµ¯Á¦Æ½ºâ£¬½èÖúÓÚºú¿Ë¶¨ÂÉ£¬¼´¿ÉÇó½â£»
£¨2£©AͬѧÔËÓõ¯»ÉµÄµ¯ÐÔÊÆÄÜת»¯ÎªÖØÁ¦ÊÆÄÜÀ´²âÁ¿ÐαäÁ¿£¬¶øBͬѧÔòÊÇÔËÓõ¯»ÉµÄµ¯ÐÔÊÆÄÜת»¯Îª¶¯ÄÜ£¬²¢½èÖúÓÚ×öƽÅ×Ô˶¯À´Ëã³ö³õËÙ¶È£¬´Ó¶ø¼´¿ÉÇó½â£»
£¨3£©·Ö±ð´ÓʵÑé¹ý³ÌÖУ¬È¥·ÖÎöÓ°ÏìʵÑé½á¹ûµÄÒòËØ£¬´Ó¶øÌá¸ßʵÑéµÄ׼ȷÐÔ

½â´ð ½â£º£¨1£©A¡¢BÁ½Î»Í¬Ñ§½øÐÐͼ¼×ËùʾµÄʵÑé¶¼½øÐÐÐαäÁ¿µÄ²âÁ¿£¬Ä¿µÄÊÇΪÁËÈ·¶¨µ¯»ÉµÄ¾¢¶ÈϵÊý£»¸ù¾Ýºú¿Ë¶¨ÂÉk=$\frac{mg}{¡÷x}$£¬ÔòÓÐk=$\frac{mg}{d}$£»
£¨2£©AͬѧÔËÓÃÎïÌåÔÚµ¯»ÉµÄµ¯Á¦×÷ÓÃÏ£¬½«µ¯»ÉÊÆÄÜת»¯ÎªÖØÁ¦ÊÆÄÜ
£¨3£©Aͬѧ£¬¸ù¾Ýµ¯»ÉµÄµ¯ÐÔÊÆÄÜת»¯ÎªÖØÁ¦ÊÆÄÜ£¬
ÔòÓУº$\frac{1}{2}$kx2=mgH
k=$\frac{mg}{d}$£¬
ÓÉÉϽâµÃ£ºx=$\sqrt{2dH}$
Bͬѧ£¬µ¯»ÉµÄµ¯ÐÔÊÆÄÜת»¯Îª¶¯ÄÜ£¬¶ø¶¯ÄÜÔò½èÖúÓÚÆ½Å×Ô˶¯À´²âµÃ³õËÙ¶È£®
ÔòÓÉË®Æ½Î»ÒÆÓëÊúÖ±¸ß¶È¿ÉµÃˮƽ³õËÙ¶È£ºv0=$\frac{L}{\sqrt{\frac{2h}{g}}}$=L $\sqrt{\frac{g}{2h}}$£¬
ËùÒÔ£º$\frac{1}{2}$k£¨ $\frac{mg}{d}$£©2=$\frac{1}{2}$m£¨L$\sqrt{\frac{g}{2h}}$ £©2
½âµÃ£ºx=L$\sqrt{\frac{d}{2h}}$ ¶øÕâÁ½Î»Í¬Ñ§¾ùÓÐÎó²î³öÏÖ£¬Aͬѧ£º²»Ò×¾«È·È·¶¨Ð¡ÇòÉÏÉýµÄ×î´ó¸ß¶È£¬¶øÇÒСÇòÉÏÉýʱÓпÉÄÜÓëËÜÁϹÜÄÚ±Ú½Ó´¥£¬²úÉúĦ²Á´Ó¶ø´øÀ´ÊµÑéÎó²î£®
Bͬѧ£ºÊµÑéʱ£¬Ð¡ÌúÇòÓë×ÀÃæÖ®¼äµÄĦ²Á»á¸øÊµÑé´øÀ´Îó²î£®
¹Ê´ð°¸Îª£º£¨1£©$\frac{mg}{d}$£¨2£©$\sqrt{2dH}$£¬L$\sqrt{\frac{d}{2h}}$£»£¨3£©AͬѧʵÑéʱ£¬²»Ò×¾«È·È·¶¨Ð¡ÇòÉÏÉýµÄ×î´ó¸ß¶È£¬¶øÇÒСÇòÉÏÉýʱÓпÉÄÜÓëËÜÁϹÜÄÚ±Ú½Ó´¥£¬²úÉúĦ²Á´Ó¶ø´øÀ´ÊµÑéÎó²î£®
BͬѧʵÑéʱ£¬Ð¡ÌúÇòÓë×ÀÃæÖ®¼äµÄĦ²Á»á¸øÊµÑé´øÀ´Îó²î

µãÆÀ ±¾Ì⿼²éÈçºÎ²âÁ¿µ¯»ÉµÄÐαäÁ¿£¬²¢Í¨¹ý²»Í¬µÄʵÑéÈ¥Éè¼Æ¡¢²âÁ¿£¬²¢´¦ÀíÊý¾Ý£¬×îºóÊý¾ÝÎó²î·ÖÎö£¬´Ó¶ø¼¤·¢Ñ§ÉúµÄѧϰÐËȤ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø