10.若函数$f(x)=\left\{{\begin{array}{l}{\frac{{3(1-{2^x})}}{{{2^x}+1}},(-1≤x≤1)}\\{-\frac{1}{4}({x^3}+3x),(x<-1或x>1)}\end{array}}\right.$对任意的m∈[-3,2],总有f(mx-1)+f(x)>0恒成立,则x的取值范围是( )
| A. | $({-\frac{1}{2},\frac{1}{3}})$ | B. | (-1,2) | C. | $({-\frac{4}{3},-\frac{1}{2}})$ | D. | (-2,3) |
9.已知数列{xn}满足xn+2=|xn+1-xn|(n∈N*),若x1=1,x2=a(a≤1,a≠0),且xn+3=xn对于任意正整数n均成立,则数列{xn}的前2016项和S2016的值为( )
| A. | 672 | B. | 673 | C. | 1342 | D. | 1344 |
4.已知平面向量$\overrightarrow{a}$,$\overrightarrow{b}$,$\overrightarrow c$满足|$\overrightarrow{a}$|=|$\overrightarrow{b}$|=1,$\overrightarrow{a}$⊥($\overrightarrow{a}$-2$\overrightarrow{b}$),$(\overrightarrow c-2\overrightarrow a)•(\overrightarrow c-\overrightarrow b)=0$,则|$\overrightarrow c$|的最大值为( )
| A. | 0 | B. | $\sqrt{3}$ | C. | $\frac{\sqrt{7}+\sqrt{3}}{2}$ | D. | $\sqrt{7}$ |
3.已知(1-2x)2017=a0+a1(x-1)+a2(x-1)2+…+a2016(x-1)2016+a2017(x-1)2017(x∈R),则a1-2a2+3a3-4a4+…-2016a2016+2017a2017=( )
0 237072 237080 237086 237090 237096 237098 237102 237108 237110 237116 237122 237126 237128 237132 237138 237140 237146 237150 237152 237156 237158 237162 237164 237166 237167 237168 237170 237171 237172 237174 237176 237180 237182 237186 237188 237192 237198 237200 237206 237210 237212 237216 237222 237228 237230 237236 237240 237242 237248 237252 237258 237266 266669
| A. | 2017 | B. | 4034 | C. | -4034 | D. | 0 |