(Ⅰ)求证:BE∥平面PDF
(Ⅱ)求PD与平面PAB所成角的正弦值.
已知函数f(x)=1-2sin2
.
(Ⅰ)在区间[
,
]上任取x0,求满足f(x0)≥
的概率;
(Ⅱ)若f(α)=
,α为第四象限角,求
的值.
| x |
| 2 |
(Ⅰ)在区间[
| π |
| 2 |
| π |
| 2 |
| 1 |
| 2 |
(Ⅱ)若f(α)=
2
| ||
| 3 |
| sin(π-2α)+cos(π+α) |
| tanα |
| x |
| 2 |
| π |
| 2 |
| π |
| 2 |
| 1 |
| 2 |
2
| ||
| 3 |
| sin(π-2α)+cos(π+α) |
| tanα |