题目内容
已知在△ABC中,C=2A,cosA=
,且
=-27.
(1)求cosB的值;
(2)求AC的长度.
[解析] (1)∵C=2A,∴cosC=cos2A=2cos2A-1=
,
∴sinC=
,sinA=
.
∴cosB=-cos(A+C)=sinAsinC-cosAcosC
=
×
-
×
=
.
(2)∵
=
,∴AB=
BC.
∵2
=-27,cosB=
,
∴|
=24,
∴BC2=16,AB=6,
练习册系列答案
相关题目
题目内容
已知在△ABC中,C=2A,cosA=
,且
=-27.
(1)求cosB的值;
(2)求AC的长度.
[解析] (1)∵C=2A,∴cosC=cos2A=2cos2A-1=
,
∴sinC=
,sinA=
.
∴cosB=-cos(A+C)=sinAsinC-cosAcosC
=
×
-
×
=
.
(2)∵
=
,∴AB=
BC.
∵2
=-27,cosB=
,
∴|
=24,
∴BC2=16,AB=6,