题目内容

19.“$\left\{\begin{array}{l}{{x}_{1}>3}\\{{x}_{2}>3}\end{array}\right.$”是“$\left\{\begin{array}{l}{{x}_{1}+{x}_{2}>6}\\{{x}_{1}{x}_{2}>9}\end{array}\right.$”成立的(  )
A.充分非必要条件B.必要非充分条件
C.非充分非必要条件D.充要条件

分析 由“$\left\{\begin{array}{l}{{x}_{1}>3}\\{{x}_{2}>3}\end{array}\right.$”推出“$\left\{\begin{array}{l}{{x}_{1}+{x}_{2}>6}\\{{x}_{1}{x}_{2}>9}\end{array}\right.$”成立,反之不成立,即可判断出结论.

解答 解:由“$\left\{\begin{array}{l}{{x}_{1}>3}\\{{x}_{2}>3}\end{array}\right.$”可以推出“$\left\{\begin{array}{l}{{x}_{1}+{x}_{2}>6}\\{{x}_{1}{x}_{2}>9}\end{array}\right.$”成立,反之不成立,例如取x1=7,x2=2.
∴“$\left\{\begin{array}{l}{{x}_{1}>3}\\{{x}_{2}>3}\end{array}\right.$”推出“$\left\{\begin{array}{l}{{x}_{1}+{x}_{2}>6}\\{{x}_{1}{x}_{2}>9}\end{array}\right.$”成立的乘法不必要条件.
故选:A.

点评 本题考查了不等式的性质、充要条件的判定方法,考查了推理能力与计算能力,属于中档题.

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