题目内容

如图所示,在平行六面体ABCD-A′B′C′D′中,
AB
=
a
,
AD
=
b
,
AA′
=
c
,P是CA′的中点,M是CD′的中点,N是C′D′的中点,点Q在CA′上,且CQ:QA′=4:1,用基底{
a
,
b
,
c
}表示以下向量:(1)
AP
;(2)
AM
;(3)
AN
;(4)
AQ
.
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连接AC,AD′.
(1)
AP
=
1
2
(
AC
+
AA′
)
=
1
2
(
AB
+
AD
+
AA′
)
=
1
2
(
a
+
b
+
c
)
.
(2)
AM
=
1
2
(
AC
+
AD′
)
=
1
2
(
AB
+2
AD
+
AA′
)
=
1
2
(
a
+2
b
+
c
)
;
(3)
AN
=
1
2
(
AC′
+
AD′
)
=
1
2
[(
AB
+
AD
+
AA′
)+(
AD
+
AA′
)]
=
1
2
(
AB
+2
AD
+2
AA′
)
=
1
2
a
+
b
+
c
;
(4)
AQ
=
AC
+
CQ
=
AC
+
4
5
(
AA′
-
AC
)
═
1
5
AC
+
4
5
AA′
=
1
5
AB
+
1
5
AD
+
4
5
AA′
=
1
5
a
+
1
5
b
+
4
5
c
.
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