题目内容
(Ⅰ)已知log189=a,18b=5,试用a、b表示log1845的值;
(Ⅱ)已知log147=a,log145=b,用a、b表示log3528.
(Ⅱ)已知log147=a,log145=b,用a、b表示log3528.
考点:对数的运算性质
专题:函数的性质及应用
分析:(Ⅰ)由已知得log189=a,log185=b,由log1845=log185+log189能求出结果.
(Ⅱ)由log3528=
=
能求出结果.
(Ⅱ)由log3528=
| log1428 |
| log1435 |
| log1414+log142 |
| log147+log145 |
解答:
解:(Ⅰ)∵log189=a,18b=5,
∴log185=b,
∴log1845=log185+log189=a+b.
(Ⅱ)∵log147=a,log145=b,
∴log3528=
=
=
=
.
∴log185=b,
∴log1845=log185+log189=a+b.
(Ⅱ)∵log147=a,log145=b,
∴log3528=
| log1428 |
| log1435 |
=
| log1414+log142 |
| log147+log145 |
=
1+log14
| ||
| a+b |
=
| 2-a |
| a+b |
点评:本题考查对数值的表示,是基础题,解题时要认真审题,注意对数运算性质的合理运用.
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