题目内容
如图所示,设A为△ABC所在平面外一点,HD=2CH,G为BH的中点
(1)试用
,
,
表示
(2)若∠BAC=60°,∠CAD=∠DAB=45°,|
|=|
|=2,|
|=3,求|
|

(1)试用
| AB |
| AC |
| AD |
| AG |
(2)若∠BAC=60°,∠CAD=∠DAB=45°,|
| AB |
| AC |
| AD |
| AG |
(1)
=
(
+
)=
(
+
+
)
=
(
+
+
)
=
+
+
(
-
)
=
+
+
(6分)
(2)|
|2=|
+
+
|2=(
+
+
)2
×4+
×4+
×9+
×2cos60°+
×2×3cos45°+
×2×2×3cos45°=
+
(8分)
=
(12分),
| AG |
| 1 |
| 2 |
| AB |
| AH |
| 1 |
| 2 |
| AB |
| AC |
| CA |
=
| 1 |
| 2 |
| AB |
| AC |
| 1 |
| 3 |
| CD |
=
| 1 |
| 2 |
| AB |
| 1 |
| 2 |
| AC |
| 1 |
| 6 |
| AD |
| AC |
=
| 1 |
| 2 |
| AB |
| 1 |
| 3 |
| AC |
| 1 |
| 6 |
| AC |
(2)|
| AG |
| 1 |
| 2 |
| AB |
| 1 |
| 3 |
| AC |
| 1 |
| 6 |
| AD |
| 1 |
| 2 |
| AB |
| 1 |
| 3 |
| AC |
| 1 |
| 6 |
| AD |
| 1 |
| 4 |
| 1 |
| 9 |
| 1 |
| 36 |
| 1 |
| 3 |
| 1 |
| 9 |
| 1 |
| 6 |
| 85 |
| 36 |
30
| ||
| 36 |
| AG |
| ||||
| 6 |
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