Question

化简①式，求②的值：
①

x- 2 3 y 1 2

(x-1y 1 2 )(x 1 3 y- 1 6 )

(x＞0，y＞0)；
②log3

27

+lg25+lg4+7log72+(-9.8)0．

Answer 1

①原式=x-

2

3

+1-

1

3

•y

1

2

-

1

2

+

1

6

=y

1

6

．
②原式=

1

2

log333+lg(25×4)+2+1
=

3

2

+2+2+1=

13

2

．