题目内容
设Sn,Tn分别为等差数列{an}与{bn}的前n项和,且
=
,则
= .
| an |
| bn |
| 4n+2 |
| 2n-5 |
| S19 |
| T19 |
考点:等差数列的前n项和
专题:等差数列与等比数列
分析:利用等差数列的前n项和公式和通项公式求解.
解答:
解:由题意知:
=
=
=
=
=
=
=
.
故答案为:
.
| S19 |
| T19 |
| ||
|
=
| a1+a19 |
| b1+b19 |
=
| 2a10 |
| 2b10 |
| a10 |
| b10 |
| 4×10+2 |
| 2×10-5 |
| 42 |
| 15 |
| 14 |
| 5 |
故答案为:
| 14 |
| 5 |
点评:本题考查两个等差数列的前19项和的比值的求法,是基础题,解题时要注意等差数列的性质的合理运用.
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