ÌâÄ¿ÄÚÈÝ

11£®ÏÂÁи÷×éÀë×ÓÔÚÖ¸¶¨»·¾³ÖÐÄÜ´óÁ¿¹²´æµÄÊÇ£¨¡¡¡¡£©
A£®ÔÚc£¨CO32-£©=0.1 mol•L-1µÄÈÜÒºÖУºK+¡¢AlO2-¡¢Cl-¡¢NO3-
B£®ÔÚ³£ÎÂÏÂÓÉË®µçÀë³öµÄc£¨OH-£©=1¡Á10-12 mol•L-1µÄÈÜÒºÖУºFe2+¡¢ClO-¡¢Na+¡¢SO42-
C£®ÔÚ¼ÓÈë±½·Ó»áÏÔ×ÏÉ«µÄÈÜÒºÖУºNH4+¡¢Cl-¡¢Na+¡¢SCN-
D£®ÔÚÄÜʹÀ¶É«Ê¯ÈïÊÔÖ½±äºìµÄÈÜÒºÖУºS2O32-¡¢CO32-¡¢Na+¡¢K+

·ÖÎö A£®¸Ã×éÀë×ÓÖ®¼ä²»·´Ó¦£»
B£®³£ÎÂÏÂÓÉË®µçÀë³öµÄc£¨OH-£©=1¡Á10-12 mol•L-1µÄÈÜÒº£¬ÎªËá»ò¼îÈÜÒº£»
C£®¼ÓÈë±½·Ó»áÏÔ×ÏÉ«µÄÈÜÒº£¬º¬ÌúÀë×Ó£»
D£®ÄÜʹÀ¶É«Ê¯ÈïÊÔÖ½±äºìµÄÈÜÒº£¬ÏÔËáÐÔ£®

½â´ð ½â£ºA£®¸Ã×éÀë×ÓÖ®¼ä²»·´Ó¦£¬¿É´óÁ¿¹²´æ£¬¹ÊAÕýÈ·£»
B£®³£ÎÂÏÂÓÉË®µçÀë³öµÄc£¨OH-£©=1¡Á10-12 mol•L-1µÄÈÜÒº£¬ÎªËá»ò¼îÈÜÒº£¬¼îÐÔÈÜÒºÖв»ÄÜ´óÁ¿´æÔÚFe2+£¬ËáÈÜÒºÖÐFe2+¡¢ClO-·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬²»Äܹ²´æ£¬¹ÊB´íÎó£»
C£®¼ÓÈë±½·Ó»áÏÔ×ÏÉ«µÄÈÜÒº£¬º¬ÌúÀë×Ó£¬ÓëSCN-½áºÏÉú³ÉÂçºÏÀë×Ó£¬²»Äܹ²´æ£¬¹ÊC´íÎó£»
D£®ÄÜʹÀ¶É«Ê¯ÈïÊÔÖ½±äºìµÄÈÜÒº£¬ÏÔËáÐÔ£¬²»ÄÜ´óÁ¿´æÔÚS2O32-¡¢CO32-£¬¹ÊD´íÎó£»
¹ÊÑ¡A£®

µãÆÀ ±¾Ì⿼²éÀë×Ó¹²´æ£¬Îª¸ßƵ¿¼µã£¬°ÑÎÕϰÌâÖеÄÐÅÏ¢¼°Àë×ÓÖ®¼äµÄ·´Ó¦Îª½â´ðµÄ¹Ø¼ü£¬²àÖØ·ÖÎöÓëÓ¦ÓÃÄÜÁ¦µÄ¿¼²é£¬×¢Ò⸴·Ö½â·´Ó¦¡¢ÂçºÏ·´Ó¦¡¢Ñõ»¯»¹Ô­·´Ó¦µÄÅжϣ¬ÌâÄ¿ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø