ÌâÄ¿ÄÚÈÝ

µç½â×°ÖÃÈçͼ£¬µç½â²ÛÄÚ×°ÓÐKI¼°µí·ÛÈÜÒº£¬ÖмäÓÃÒõÀë×Ó½»»»Ä¤¸ô¿ª£®ÔÚÒ»¶¨µÄµçѹÏÂͨµç£¬·¢ÏÖ×ó²àÈÜÒº±äÀ¶É«£¬Ò»¶Îʱ¼äºó£¬À¶É«Öð½¥±ädz£®ÒÑÖª£º3I2+6OH-=IO3-+5I-+3H2O£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢ÓҲ෢ÉúµÄµç¼«·½³Ìʽ£ºO2+4e-+2H2O=4OH-
B¡¢µç½â²ÛÄÚ·¢Éú·´Ó¦µÄ×Ü»¯Ñ§·½³ÌʽÊÇKI+3H2O=KIO3+3H2¡ü
C¡¢µç½â½áÊøºó£¬ÓÒ²àÈÜÒºÖв»¿ÉÄܺ¬ÓÐIO3-
D¡¢Èç¹ûÓÃÑôÀë×Ó½»»»Ä¤´úÌæÒõÀë×Ó½»»»Ä¤£¬µç½â²ÛÄÚ·´Ó¦µÄ×Ü»¯Ñ§·½³Ìʽ²»±ä
¿¼µã£ºµç½âÔ­Àí
רÌ⣺
·ÖÎö£º×ó²àÈÜÒº±äÀ¶É«£¬Éú³ÉI2£¬×ó²àµç¼«ÎªÑô¼«£¬µç¼«·´Ó¦Îª£º2I--2e-=I2£¬ÓÒ²àµç¼«ÎªÒõ¼«£¬µç¼«·´Ó¦Ê½Îª£º2H2O+2e-=H2¡ü+2OH-£¬ÓÒ²à·Å³öÇâÆø£¬ÓÒ²àI-¡¢OH-ͨ¹ýÒõÀë×Ó½»»»Ä¤Ïò×ó²àÒÆ¶¯£¬·¢Éú·´Ó¦3I2+6OH-=IO3-+5I-+3H2O£¬Ò»¶Îʱ¼äºó£¬À¶É«±ädz£¬±£Ö¤Á½±ßÈÜÒº³ÊµçÖÐÐÔ£¬×ó²àµÄIO3-ͨ¹ýÒõÀë×Ó½»»»Ä¤ÏòÓÒ²àÒÆ¶¯£¬Èç¹ûÓÃÑôÀë×Ó½»»»Ä¤´úÌæÒõÀë×Ó½»»»Ä¤£¬×ó²à¶àÓàK+ͨ¹ýÑôÀë×Ó½»»»Ä¤Ç¨ÒÆÖÁÒõ¼«£¬±£Ö¤Á½±ßÈÜÒº³ÊµçÖÐÐÔ£®
½â´ð£º ½â£ºA£®×ó²àÈÜÒº±äÀ¶É«£¬Éú³ÉI2£¬×ó²àµç¼«ÎªÑô¼«£¬ÓÒ²àµç¼«ÎªÒõ¼«£¬µç¼«·´Ó¦Ê½Îª£º2H2O+2e-=H2¡ü+2OH-£¬¹ÊA´íÎó£»
B£®×ó²àµç¼«ÎªÑô¼«£¬µç¼«·´Ó¦Îª£º2I--2e-=I2£¬Í¬Ê±·¢Éú·´Ó¦3I2+6OH-=IO3-+5I-+3H2O£¬ÓÒ²àµç¼«ÎªÒõ¼«£¬µç¼«·´Ó¦Ê½Îª£º2H2O+2e-=H2¡ü+2OH-£¬¹Ê×ܵĵ缫·´Ó¦Ê½Îª£ºKI+3H2O
 µç½â 
.
 
KIO3+3H2¡ü£¬¹ÊBÕýÈ·£»
C£®Ò»¶Îʱ¼äºó£¬À¶É«±ädz£¬·¢Éú·´Ó¦3I2+6OH-=IO3-+5I-+3H2O£¬ÖмäΪÒõÀë×Ó½»»»Ä¤£¬ÓÒ²àI-¡¢OH-ͨ¹ýÒõÀë×Ó½»»»Ä¤Ïò×ó²àÒÆ¶¯£¬±£Ö¤Á½±ßÈÜÒº³ÊµçÖÐÐÔ£¬×ó²àµÄ
IO3-ͨ¹ýÒõÀë×Ó½»»»Ä¤ÏòÓÒ²àÒÆ¶¯£¬¹ÊÓÒ²àÈÜÒºÖк¬ÓÐIO3-£¬¹ÊC´íÎó£»
D£®Èç¹ûÓÃÑôÀë×Ó½»»»Ä¤´úÌæÒõÀë×Ó½»»»Ä¤£¬×ó²àµç¼«ÎªÑô¼«£¬µç¼«·´Ó¦Îª£º2I--2e-=I2£¬ÓÒ²àµç¼«ÎªÒõ¼«£¬µç¼«·´Ó¦Ê½Îª£º2H2O+2e-=H2¡ü+2OH-£¬±£Ö¤Á½±ßÈÜÒº³ÊµçÖÐÐÔ£¬×ó²à¶àÓàK+ͨ¹ýÑôÀë×Ó½»»»Ä¤Ç¨ÒÆÖÁÒõ¼«£¬×ó²àÉú³ÉI2£¬ÓÒ²àÈÜÒºÖÐÓÐKOHÉú³É£¬µâµ¥ÖÊÓëKOH²»ÄÜ·´Ó¦£¬×Ü·´Ó¦Ï൱ÓÚ£º2KI+2H2O
 µç½â 
.
 
2KOH+I2+H2¡ü£¬¹ÊD´íÎó£»
¹ÊÑ¡B£®
µãÆÀ£º±¾Ì⿼²éµç½âÔ­Àí£¬ÄѶÈÖеȣ¬×¢ÒâDÑ¡ÏîΪÒ×´íµã£¬×¢ÒâÇâÑõ¸ù²»ÄÜͨ¹ýÑôÀë×Ó½»»»Ä¤£¬²»ÄÜÓëµâµ¥ÖÊ·¢Éú·´Ó¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø