2.如图,△ABC中∠A=30°,E是AC边上的点,先将△ABE沿着BE翻折,翻折后△ABE的AB边交AC于点D,又将△BCD沿着BD翻折,C点恰好落在BE上,此时∠CDB=82°,则原三角形的∠B为( )

| A. | 75° | B. | 76° | C. | 77° | D. | 78° |
20.
如图,在平行四边形ABCD中,点E是边AD上一点,且AE=2ED,EC交对角线BD于点F,则$\frac{EF}{FC}$等于( )
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| A. | $\frac{1}{2}$ | B. | $\frac{1}{3}$ | C. | $\frac{2}{3}$ | D. | $\frac{3}{2}$ |