题目内容

8.已知$\left\{\begin{array}{l}{x=1}\\{y=2}\end{array}\right.$是二元一次方程组$\left\{\begin{array}{l}{3x+2y=m}\\{nx-y=1}\end{array}\right.$的解,则m-n的值是4.

分析 将$\left\{\begin{array}{l}{x=1}\\{y=2}\end{array}\right.$代入方程组$\left\{\begin{array}{l}{3x+2y=m}\\{nx-y=1}\end{array}\right.$得:$\left\{\begin{array}{l}{m=7}\\{n=3}\end{array}\right.$,继而可得答案.

解答 解:将$\left\{\begin{array}{l}{x=1}\\{y=2}\end{array}\right.$代入方程组$\left\{\begin{array}{l}{3x+2y=m}\\{nx-y=1}\end{array}\right.$,得:$\left\{\begin{array}{l}{m=7}\\{n=3}\end{array}\right.$,
则m-n=4,
故答案为:4

点评 本题主要考查方程组的解,熟练掌握二元一次方程组的解的定义是解题的关键.

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