题目内容
18.若关于x、y的二元一次方程组$\left\{\begin{array}{l}{ax-my=16}\\{bx+ny=15}\end{array}\right.$的解是$\left\{\begin{array}{l}{x=7}\\{y=-1}\end{array}\right.$,那么关于x、y的二元一次方程组$\left\{\begin{array}{l}{a(2x+y)-m(x-y)=16}\\{b(2x+y)+n(x-y)=15}\end{array}\right.$的解是$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$.分析 根据题中方程组的解,把2x+y与x-y看做整体,求出解即可.
解答 解:根据题意得:$\left\{\begin{array}{l}{2x+y=7}\\{x-y=-1}\end{array}\right.$,
解得:$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$,
故答案为:$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$
点评 此题考查了解二元一次方程组,利用了消元的思想,消元的方法有:代入消元法与加减消元法.
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