题目内容

10.已知2a-y+5b3x与-5a2xb2+4y是同类项,则(  )
A.$\left\{\begin{array}{l}{x=2}\\{y=-1}\end{array}\right.$B.$\left\{\begin{array}{l}{x=2}\\{y=1}\end{array}\right.$C.$\left\{\begin{array}{l}{x=1}\\{y=-2}\end{array}\right.$D.$\left\{\begin{array}{l}{x=3}\\{y=-2}\end{array}\right.$

分析 根据题意,利用同类项定义列出方程组,求出方程组的解即可得到结果.

解答 解:∵2a-y+5b3x与-5a2xb2+4y是同类项,
∴$\left\{\begin{array}{l}{-y+5=2x}\\{3x=2+4y}\end{array}\right.$,
解得:$\left\{\begin{array}{l}{x=2}\\{y=1}\end{array}\right.$,
故选B

点评 此题考查了解二元一次方程组,利用了消元的思想,消元的方法有:代入消元法与加减消元法.

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