题目内容
计算:
(1)(xy-x2)•
÷
;
(2)1-(x-
)2÷
.
(1)(xy-x2)•
| xy |
| x2-2xy+y2 |
| x2 |
| x-y |
(2)1-(x-
| 1 |
| 1-x |
| x2-x+1 |
| x2-2x+1 |
考点:分式的混合运算
专题:计算题
分析:(1)原式利用除法法则变形,约分即可得到结果;
(2)原式先计算乘方运算,再计算除法运算,最后算加减运算即可得到结果.
(2)原式先计算乘方运算,再计算除法运算,最后算加减运算即可得到结果.
解答:解:(1)原式=x(y-x)•
•
=-x(x-y)•
•
=-y;
(2)原式=1-[
]2•
=1-
•
=1-1
=0.
| xy |
| (x-y)2 |
| x-y |
| x2 |
=-x(x-y)•
| xy |
| (x-y)2 |
| x-y |
| x2 |
=-y;
(2)原式=1-[
| x(1-x)-1 |
| 1-x |
| (x-1)2 |
| x2-x+1 |
=1-
| x2-x+1 |
| (x-1)2 |
| (x-1)2 |
| x2-x+1 |
=1-1
=0.
点评:此题考查了分式的混合运算,熟练掌握运算法则是解本题的关键.
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