题目内容

14.二元一次方程组$\left\{\begin{array}{l}{3x+2y=6}\\{y=x-2}\end{array}\right.$的解是(  )
A.$\left\{\begin{array}{l}{x=\frac{1}{2}}\\{y=-\frac{3}{2}}\end{array}\right.$B.$\left\{\begin{array}{l}{x=2}\\{y=0}\end{array}\right.$C.$\left\{\begin{array}{l}{x=-\frac{3}{2}}\\{y=\frac{1}{2}}\end{array}\right.$D.$\left\{\begin{array}{l}{x=0}\\{y=-2}\end{array}\right.$

分析 方程组利用代入消元法求出解即可.

解答 解:$\left\{\begin{array}{l}{3x+2y=6①}\\{y=x-2②}\end{array}\right.$,
把②代入①得:3x+2x-4=6,
解得:x=2,
把x=2代入②得:y=0,
则方程组的解为$\left\{\begin{array}{l}{x=2}\\{y=0}\end{array}\right.$,
故选B.

点评 此题考查了解二元一次方程组,利用了消元的思想,消元的方法为:加减消元法与代入消元法.

练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网