题目内容

4.与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解的方程组是(  )
A.$\left\{\begin{array}{l}{x-y=1}\\{3x=5-y}\end{array}\right.$B.$\left\{\begin{array}{l}{x=y-1}\\{3x=5-y}\end{array}\right.$C.$\left\{\begin{array}{l}{x=y-1}\\{3x+5+y=0}\end{array}\right.$D.$\left\{\begin{array}{l}{x=y-1}\\{3x+5-y=0}\end{array}\right.$

分析 首先根据二元一次方程组的求解方法,求出方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$的解是多少;然后判断出方程组的解是四个选项中哪个方程组的解,即可判断出与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解的方程组是哪个.

解答 解:由$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$,
解得$\left\{\begin{array}{l}{x=-1.5}\\{y=-0.5}\end{array}\right.$;
因为(-1.5)-(-0.5)=-1≠1,
所以A不与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解;
因为3×(-1.5)=-4.5,5-(-0.5)=5.5,-4.5≠5.5,
所以B不与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解;
因为3×(-1.5)+5-(-0.5)
=-4.5+5+0.5
=1,
所以D不与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解;
因为-1.5=-0.5-1,
3×(-1.5)+5+(-0.5)
=-4.5+5-0.5
=0,
所以C与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解,
因此与方程组$\left\{\begin{array}{l}{x+3y=-3}\\{x+y=-2}\end{array}\right.$有相同解的方程组是$\left\{\begin{array}{l}{x=y-1}\\{3x+5+y=0}\end{array}\right.$.
故选:C.

点评 (1)此题主要考查了同解方程组,解答此题的关键是要明确:如果两个方程组的解相同,那么这两个方程组就是同解方程组.
(2)此题还考查了二元一次方程组的求解问题,要熟练掌握二元一次方程组的求解方法.

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