题目内容
(1)∠AOB+∠BOC=
(2)∠AOC+
(3)∠BOD-∠COD=
(4)∠AOD-
(5)∠AOD=
(6)∠BOC=∠AOD-
考点:角的计算
专题:
分析:仔细看图形利用角的和差关系填空即可.
解答:解:(1)∠AOB+∠BOC=∠AOC;
(2)∠AOC+∠DOC=∠AOD;
(3)∠BOD-∠COD=∠BOC;
(4)∠AOD-∠DOB=∠AOB;
(5)∠AOD=∠AOB+∠BOC+∠COD=∠AOB+∠BOD=∠AOC+∠DOC;
(6)∠BOC=∠AOD-∠DOC-∠AOB=∠AOC-∠AOB=∠DOB-∠DOC.
故答案为:(1)∠AOC;(2)∠DOC;(3)∠BOC;(4)∠DOB;(5)∠AOB,∠BOC,∠COD,∠AOB,∠BOD,∠AOC,∠DOC;(6)∠DOC,∠AOB,∠AOC,∠AOB,∠DOB,∠DOC.
(2)∠AOC+∠DOC=∠AOD;
(3)∠BOD-∠COD=∠BOC;
(4)∠AOD-∠DOB=∠AOB;
(5)∠AOD=∠AOB+∠BOC+∠COD=∠AOB+∠BOD=∠AOC+∠DOC;
(6)∠BOC=∠AOD-∠DOC-∠AOB=∠AOC-∠AOB=∠DOB-∠DOC.
故答案为:(1)∠AOC;(2)∠DOC;(3)∠BOC;(4)∠DOB;(5)∠AOB,∠BOC,∠COD,∠AOB,∠BOD,∠AOC,∠DOC;(6)∠DOC,∠AOB,∠AOC,∠AOB,∠DOB,∠DOC.
点评:本题主要考查了角的和差关系,仔细观察图形是解题的关键.
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