题目内容
已知a、b、c为实数,且
=3,
=4,
=5.
(1)求
+
+
的值;
(2)求
的值;
(3)分别求a、b、c的值.
| a+b |
| ab |
| b+c |
| bc |
| c+a |
| ca |
(1)求
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
(2)求
| ab+bc+ca |
| abc |
(3)分别求a、b、c的值.
考点:分式的化简求值
专题:
分析:(1)由
=3,
=4,
=5得出
+
=3,
+
=4,
+
=5,两边分别相加,进一步整理得出
+
+
的数值;
(2)化为(1)的形式求得答案即可;
(3)由(1)中的数值,分别减去已知条件,求得答案即可.
| a+b |
| ab |
| b+c |
| bc |
| c+a |
| ca |
| 1 |
| a |
| 1 |
| b |
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
(2)化为(1)的形式求得答案即可;
(3)由(1)中的数值,分别减去已知条件,求得答案即可.
解答:解:(1)∵
=3,
=4,
=5,
∴
+
=3,
+
=4,
+
=5,
∴2(
+
+
)=3+4+5=12,
∴
+
+
=6;
(2)
=
+
+
=6;
(3)∵
+
+
=6,
+
=3,
+
=4,
+
=5
∴
=2,
=1,
=3,
∴a=
,b=1,c=
.
| a+b |
| ab |
| b+c |
| bc |
| c+a |
| ca |
∴
| 1 |
| a |
| 1 |
| b |
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
∴2(
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
∴
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
(2)
| ab+bc+ca |
| abc |
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
(3)∵
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| b |
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
∴
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
∴a=
| 1 |
| 2 |
| 1 |
| 3 |
点评:此题考查分式的化简求值,注意利用已知条件,把原式化简变形,利用等式的性质解决问题.
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