题目内容
先化简,再求值:(
-
)÷
,其中x=2.
| x+1 |
| x2-1 |
| 1 |
| 1-x |
| x+2 |
| x2-x |
考点:分式的化简求值
专题:
分析:先将括号内的部分因式分解,约分后再将除法转化为乘法,然后代入求值.
解答:解:原式=[
-
]•
=(
+
)•
=
•
=
.
当x=2时,原式=
=1.
| x+1 |
| (x+1)(x-1) |
| 1 |
| 1-x |
| x(x-1) |
| x+2 |
=(
| 1 |
| x-1 |
| 1 |
| x-1 |
| x(x-1) |
| x+2 |
=
| 2 |
| x-1 |
| x(x-1) |
| x+2 |
=
| 2x |
| x+2 |
当x=2时,原式=
| 2×2 |
| 2+2 |
点评:本题考查了分式的化简求值,熟悉约分、通分因式分解是解题的关键.
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