题目内容

5.下列四组数值中,是二元一次方程x-3y=1的解的有(  )
①$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$      ②$\left\{\begin{array}{l}{x=4}\\{y=1}\end{array}\right.$      ③$\left\{\begin{array}{l}{x=10}\\{y=3}\end{array}\right.$     ④$\left\{\begin{array}{l}{x=5}\\{y=-2}\end{array}\right.$.
A.B.C.②③D.②④

分析 把x与y的值分别代入方程左右两边检验即可.

解答 解:①把$\left\{\begin{array}{l}{x=2}\\{y=3}\end{array}\right.$代入方程得:左边=2-9=-7,右边=1,左边≠右边,不是解;
②把$\left\{\begin{array}{l}{x=4}\\{y=1}\end{array}\right.$代入方程得:左边=4-3=1,右边=1,左边=右边,是解;
③把$\left\{\begin{array}{l}{x=10}\\{y=3}\end{array}\right.$代入方程得:左边=10-9=1,右边=1,左边=右边,是解;
④把$\left\{\begin{array}{l}{x=5}\\{y=-2}\end{array}\right.$代入方程得:左边=5+6=11,右边=1,左边≠右边,不是解,
故选C

点评 此题考查了二元一次方程的解,方程的解即为能使方程左右两边相等的未知数的值.

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