题目内容
19.计算:(1)(-1)2016+π0-${(\frac{1}{3})}^{-1}$+$\root{3}{8}$
(2)$\frac{x^2-1}{x+1}$÷$\frac{x^2-2x+1}{x^2-x}$.
分析 (1)先计算负整数指数幂、零指数幂、化简二次根式然后计算加减法;
(2)利用完全平方公式、平方差公式、化除法为乘法进行约分化简.
解答 解:(1)原式=1+1-3+2=1;
(2)原式=$\frac{(x+1)(x-1)}{x+1}$×$\frac{x(x-1)}{(x-1)^{2}}$=x.
点评 本题考查了分式的乘除法、实数的运算以及负整数指数幂等知识点,属于基础题.
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