ÌâÄ¿ÄÚÈÝ
18£®ÔÚ¡°Ì½¾¿¶¯ÄÜÓëÖØÁ¦ÊÆÄܵÄת»¯ºÍÊغ㡱µÄʵÑéÖвÉÓÃÖØÎï×ÔÓÉÏÂÂäµÄ·½·¨£º£¨1£©ÊµÑ鹩ѡÔñµÄÖØÎïÓÐÒÔÏÂËĸö£¬Ó¦Ñ¡ÔñC£®
A£®ÖÊÁ¿Îª100gµÄľÇò B£®ÖÊÁ¿Îª10gµÄíÀÂë
C£®ÖÊÁ¿Îª200gµÄ¹³Âë D£®ÖÊÁ¿Îª10gµÄËÜÁÏÇò
£¨2£©ÊµÑéÖв»Ò»¶¨£¨ÌîÒ»¶¨»ò²»Ò»¶¨£©ÒªÓÃÌìƽ²âÁ¿ÖØÎïµÄÖÊÁ¿£®
£¨3£©Èôij´ÎʵÑéÖÐʹÓÃÖÊÁ¿m=1kgµÄÖØÎï×ÔÓÉÏÂÂ䣬µÃµ½ÈçͼËùʾµÄÖ½´ø£¬ÏàÁÚ¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ôΪ0.04s£®ÄÇô´Ó´òµã¼ÆʱÆ÷´òÏÂÆðµãOµ½´òÏÂBµãµÄ¹ý³ÌÖУ¬ÖØÎïÖØÁ¦ÊÆÄܵļõÉÙÁ¿¡÷Ep=2.33J £¨g=10m/s2£¬±£ÁôÈýλÓÐЧÊý×Ö£©£¬´Ë¹ý³ÌÖÐÖØÎﶯÄܵÄÔö¼ÓÁ¿¡÷Ek=2.26J£¨±£ÁôÈýλÓÐЧÊý×Ö£©£®Óɴ˿ɵõ½µÄ½áÂÛÊÇÔÚÎó²îÔÊÐí·¶Î§ÄÚ£¬ÖØÎïµÄ»úеÄÜÊغ㣮
·ÖÎö ΪÁ˼õС×èÁ¦µÄÓ°Ï죬ÖØ´¸Ñ¡ÔñÖÊÁ¿´óһЩ£¬Ìå»ýСһЩµÄ£®
¸ù¾ÝϽµµÄ¸ß¶ÈÇó³öÖØÁ¦ÊÆÄܵļõСÁ¿£¬¸ù¾Ýij¶Îʱ¼äÄÚµÄƽ¾ùËٶȵÈÓÚÖмäʱ¿ÌµÄ˲ʱËÙ¶ÈÇó³öBµãµÄËٶȣ¬´Ó¶øµÃ³ö¶¯ÄܵÄÔö¼ÓÁ¿£¬Í¨¹ý±È½ÏµÃ³öʵÑéµÄ½áÂÛ£®
½â´ð ½â£º£¨1£©ÎªÁ˼õС×èÁ¦µÄÓ°Ï죬ÖØ´¸Ñ¡ÔñÖÊÁ¿´óһЩ£¬Ìå»ýСһЩµÄ£¬ËùÒÔÖØÎïÑ¡ÔñÖÊÁ¿Îª200gµÄ¹³Â룬¹ÊÑ¡£ºC£®
£¨2£©ÑéÖ¤¶¯ÄܵÄÔö¼ÓÁ¿ºÍÖØÁ¦ÊÆÄܵļõСÁ¿£¬Á½¶Ë¶¼ÓÐÖÊÁ¿£¬¿ÉÒÔԼȥ£¬ËùÒÔ²»Ò»¶¨ÐèÒª²âÁ¿ÖØ´¸µÄÖÊÁ¿£®
£¨3£©´Ó´òµã¼ÆʱÆ÷´òÏÂÆðµãOµ½´òÏÂBµãµÄ¹ý³ÌÖУ¬ÖØÎïÖØÁ¦ÊÆÄܵļõÉÙÁ¿¡÷Ep=mgh=1¡Á10¡Á23.25¡Á10-2J¡Ö2.33J£¬BµãµÄ˲ʱËÙ¶È${v}_{B}=\frac{{x}_{AC}}{2T}=\frac{0.3250-0.1550}{0.08}$m/s=2.125m/s£¬Ôò¶¯ÄܵÄÔö¼ÓÁ¿$¡÷{E}_{k}=\frac{1}{2}m{{v}_{B}}^{2}$=$\frac{1}{2}¡Á1¡Á2.12{5}^{2}$¡Ö2.26J£¬¿ÉÖªÔÚÎó²îÔÊÐí·¶Î§ÄÚ£¬ÖØÎïµÄ»úеÄÜÊغ㣮
¹Ê´ð°¸Îª£º£¨1£©C£¬£¨2£©²»Ò»¶¨£¬£¨3£©2.33£¬2.26£¬ÔÚÎó²îÔÊÐí·¶Î§ÄÚ£¬ÖØÎïµÄ»úеÄÜÊغ㣮
µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÕÆÎÕÖ½´øµÄ´¦Àí·½·¨£¬»á¸ù¾ÝÖ½´øÇó½â˲ʱËٶȣ¬´Ó¶øµÃ³ö¶¯ÄܵÄÔö¼ÓÁ¿£¬»á¸ù¾ÝϽµµÄ¸ß¶ÈÇó½âÖØÁ¦ÊÆÄܵļõСÁ¿£®
A£® | $\frac{\sqrt{3}¦ÐL}{3{v}_{0}}$ | B£® | $\frac{\sqrt{3}¦ÐL}{6{v}_{0}}$ | C£® | $\frac{\sqrt{3}¦ÐL}{9{v}_{0}}$ | D£® | $\frac{\sqrt{3}¦ÐL}{12{v}_{0}}$ |
A£® | UAB£ºUCD=2£º1 | |
B£® | R2Á½¶ËµçѹΪ4V | |
C£® | Ô¡¢¸±ÏßȦ»Ø·ÏûºÄµÄ¹¦ÂÊÖ®±Èp1£ºp2=1£º1 | |
D£® | ÈôAB¼ä¸Ä½ÓµçѹÈÔΪ12VµÄÖ±Á÷µçÔ´£¬ÔòÔ¡¢¸±ÏßȦ»Ø·µçÁ÷Ö®±ÈI1£ºI2=1£º2 |