题目内容
如图,已知
,过顶点A的圆与边BC切于BC的中点P,与边AB、AC分别交于点M、N,且CN=2BM,点N平分AC.则
=( )
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408232235440101631.png)
A. 2 B. 4 C. 6 D. 7
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823223543948544.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823223543963638.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408232235440101631.png)
A. 2 B. 4 C. 6 D. 7
D
证明:由切、割线定理,得BP2=BM•BA,CP2=CN•CA,
∵BP=CP,∴BM•BA=2CN2,
∵CN=NA=2BM,BA=BM+AM,
∴BM(BM+AM)=8BM2,
∴AM=7BM,
∵BP=CP,∴BM•BA=2CN2,
∵CN=NA=2BM,BA=BM+AM,
∴BM(BM+AM)=8BM2,
∴AM=7BM,
![](http://thumb.zyjl.cn/images/loading.gif)
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