题目内容
已知数列{an}满足an+1=![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823203224153826.png)
(Ⅰ)若方程f(x)=x的解称为函数y=f(x)的不动点,求an+1=f(an)的不动点的值;
(Ⅱ)若a1=2,bn=
,求证:数列{lnbn}是等比数列,并求数列{bn}的通项.
(Ⅲ)当任意nÎN*时,求证:b1+b2+b3+…+bn<![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823203224184338.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823203224153826.png)
(Ⅰ)若方程f(x)=x的解称为函数y=f(x)的不动点,求an+1=f(an)的不动点的值;
(Ⅱ)若a1=2,bn=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823203224168505.png)
(Ⅲ)当任意nÎN*时,求证:b1+b2+b3+…+bn<
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823203224184338.png)
由方程an+1=f(an)得an=
,
解得an=0,或an=?1,或an="1 " .……2分
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/2014082320322434042722.jpg)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823203224153826.png)
解得an=0,或an=?1,或an="1 " .……2分
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/2014082320322434042722.jpg)
略
![](http://thumb.zyjl.cn/images/loading.gif)
练习册系列答案
相关题目