题目内容
y=sin(3-4x),则y′=( )
A.-sin(3-4x) | B.3-cos(-4x) | C.4cos(3-4x) | D.-4cos(3-4x) |
由于y=sin(3-4x),
则y′=cos(3-4x)×(3-4x)′=-4cos(3-4x)
故选D
则y′=cos(3-4x)×(3-4x)′=-4cos(3-4x)
故选D
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