题目内容
(本大题14分)
已知函数
定义域为
,且满足
.
(Ⅰ)求
解析式及最小值;
(Ⅱ)求证:
,
。
(Ⅲ)设
。求证:
,
.
已知函数



(Ⅰ)求

(Ⅱ)求证:


(Ⅲ)设



(1)
,
(2)见解析;(3)


(2)见解析;(3)

本试题主要是考查了导数在研究函数中的运用。
(1)求解导数,然后判定单调性,然后分析最值。
(2)求解导数可知
(3)构造函数
,利用导数分析最值,进而证明不等式。
解:(1)
,
(2)求导可知:
(3)
,
故
,令
求导易知
最大值为
,而
,且
故
(1)求解导数,然后判定单调性,然后分析最值。
(2)求解导数可知

(3)构造函数

解:(1)


(2)求导可知:

(3)


故


求导易知




故


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