题目内容
如果f(x)=ax3+bx2+c(a>0)的导函数图象的顶点坐标为(1,-
),那么曲线y=f(x)上任一点的切线的倾斜角α的取值范围是( )
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
A.![]() | B.![]() ![]() |
C.![]() ![]() | D.![]() ![]() |
D
∵f′(x)=3ax2+2bx(a>0),
∴
解得![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601755923.png)
∴f′(x)=
x2-2
x=
(x-1)2-
≥-
.
即tan α≥-
,故切线倾斜角的范围是
∪
.故选D.
∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240406017391068.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601755923.png)
∴f′(x)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
即tan α≥-
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601567344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601645641.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824040601895686.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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A.![]() | B.![]() ![]() |
C.![]() ![]() | D.![]() ![]() |