ÌâÄ¿ÄÚÈÝ

16£®ÓÐA¡¢B¡¢GÈýÖÖÓлúÎËüÃÇÔÚÒ»¶¨Ìõ¼þÏÂÓëNaOHÈÜÒº·´Ó¦£®ÆäÉú³ÉÎﻹÄÜ·¢ÉúÈçͼËùʾµÄ±ä»¯£¨²¿·Ö²úÎïÂÔÈ¥£©

ÒÑÖª£º
¢ÙEÓë¼îʯ»Ò¹²ÈÈ£¬¿ÉÖƵÃÃܶÈΪ0.717 g/LµÄÆø̬Ìþ£¨±ê׼״̬ϲⶨµÄÃܶȣ©£»
¢ÚCÓëÐÂÖƵÄCu£¨OH£©2Ðü×ÇÒº¹²ÈÈÉú³ÉשºìÉ«³Áµí£»
¢ÛD¼«Ò×ÈÜÓÚË®£¬Í¨³£Çé¿öÏÂΪÎÞÉ«µ«Óд̼¤ÐÔÆøζµÄÆøÌ壬ÆäË®ÈÜÒºÖðµÎµÎÈëAgNO3ÈÜÒºÖÐ×î³õ±ä»ë×Ç£¬ÔÙ¼ÌÐøµÎÈëDÈÜÒººóÓÖ±äΪ³ÎÇåÈÜÒº£¬ËùµÃ³ÎÇåÈÜÒºÔÚÊÔ¹ÜÖÐÓëC»ìºÏ¹²ÈÈ£¬¿ÉÉú³ÉÒø¾µ£»
¢ÜGÄÜʹÐÂÖƵÄCu£¨OH£©2Ðü×ÇÒº±ä³ÎÇ壮
Çë»Ø´ð£º
£¨1£©Ð´³öÏÂÁи÷ÎïÖʵĽṹ¼òʽ£ºACH3COONH4¡¢BCH3COOCH2CH3¡¢CCH3CHO£®
£¨2£©Ð´³öÏÂÁи÷·´Ó¦µÄ»¯Ñ§·½³Ìʽ£®
¢ÙA¡úE£ºCH3COONH4+NaOH$\stackrel{¡÷}{¡ú}$CH3COONa+NH3¡ü+H2O£»
¢ÚCÓëÐÂÖƵÄCu£¨OH£©2·´Ó¦£ºCH3CHO+2Cu£¨OH£©2$\stackrel{¡÷}{¡ú}$CH3COOH+Cu2O¡ý+2H2O£®
£¨3£©Ð´³öFͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£ºCH3OCH3£®

·ÖÎö ±ê׼״̬ÏÂÃܶÈΪ0.717 g/LµÄÆø̬Ìþ£¬ÆäĦ¶ûÖÊÁ¿Îª0.717g/L¡Á22.4L/mol¡Ö16g/mol£¬ÎªCH4£¬ÒÒ´¼ÄÆÓë¼îʯ»Ò¹²ÈÈ·¢ÉúÍÑôÈ·´Ó¦Éú³É¼×Í飬ËùÒÔEΪCH3COONa£¬FÑõ»¯Éú³ÉC£¬CÑõ»¯Éú³ÉG£¬EÄܹ»Éú³ÉG£¬GÄÜʹÐÂÖƵÄCu£¨OH£©2Ðü×ÇÒº±ä³ÎÇ壬˵Ã÷GΪCH3COOH£¬FΪCH3CH2OH£¬CΪCH3CHO£¬ÔòBΪCH3COOCH2CH3£¬D¼«Ò×ÈÜÓÚË®£¬Í¨³£Çé¿öÏÂΪÎÞÉ«µ«Óд̼¤ÐÔÆøζµÄÆøÌ壬ÆäË®ÈÜÒºÖðµÎµÎÈëAgNO3ÈÜÒºÖÐ×î³õ±ä»ë×Ç£¬ÔÙ¼ÌÐøµÎÈëDÈÜÒººóÓÖ±äΪ³ÎÇåÈÜÒº£¬ËùµÃ³ÎÇåÈÜÒºÔÚÊÔ¹ÜÖÐÓëC»ìºÏ¹²ÈÈ£¬¿ÉÉú³ÉÒø¾µ£¬ËµÃ÷DΪNH3£¬AΪCH3COONH4£¬¾Ý´Ë·ÖÎö£®

½â´ð ½â£º±ê׼״̬ÏÂÃܶÈΪ0.717 g/LµÄÆø̬Ìþ£¬ÆäĦ¶ûÖÊÁ¿Îª0.717g/L¡Á22.4L/mol¡Ö16g/mol£¬ÎªCH4£¬ÒÒ´¼ÄÆÓë¼îʯ»Ò¹²ÈÈ·¢ÉúÍÑôÈ·´Ó¦Éú³É¼×Í飬ËùÒÔEΪCH3COONa£¬FÑõ»¯Éú³ÉC£¬CÑõ»¯Éú³ÉG£¬EÄܹ»Éú³ÉG£¬GÄÜʹÐÂÖƵÄCu£¨OH£©2Ðü×ÇÒº±ä³ÎÇ壬˵Ã÷˵Ã÷GΪCH3COOH£¬FΪCH3CH2OH£¬CΪCH3CHO£¬ÔòBΪCH3COOCH2CH3£¬D¼«Ò×ÈÜÓÚË®£¬Í¨³£Çé¿öÏÂΪÎÞÉ«µ«Óд̼¤ÐÔÆøζµÄÆøÌ壬ÆäË®ÈÜÒºÖðµÎµÎÈëAgNO3ÈÜÒºÖÐ×î³õ±ä»ë×Ç£¬ÔÙ¼ÌÐøµÎÈëDÈÜÒººóÓÖ±äΪ³ÎÇåÈÜÒº£¬ËùµÃ³ÎÇåÈÜÒºÔÚÊÔ¹ÜÖÐÓëC»ìºÏ¹²ÈÈ£¬¿ÉÉú³ÉÒø¾µ£¬ËµÃ÷DΪNH3£¬AΪCH3COONH4£¬
£¨1£©AΪCH3COONH4£¬BΪCH3COOCH2CH3£¬CΪCH3CHO£¬¹Ê´ð°¸Îª£ºCH3COONH4£»CH3COOCH2CH3£»CH3CHO£»
£¨2£©AΪCH3COONH4£¬AÓëNaOHÈÜÒº·´Ó¦Éú³ÉÒÒËáï§Óë°±Æø£¬»¯Ñ§·½³ÌʽΪCH3COONH4+NaOH$\stackrel{¡÷}{¡ú}$CH3COONa+NH3¡ü+H2O£¬CΪCH3CHO£¬CÓëÐÂÖƵÄCu£¨OH£©2·´Ó¦µÄ»¯Ñ§·½³ÌʽCH3CHO+2Cu£¨OH£©2$\stackrel{¡÷}{¡ú}$CH3COOH+Cu2O¡ý+2H2O£¬¹Ê´ð°¸Îª£ºCH3COONH4+NaOH$\stackrel{¡÷}{¡ú}$CH3COONa+NH3¡ü+H2O£»CH3CHO+2Cu£¨OH£©2$\stackrel{¡÷}{¡ú}$CH3COOH+Cu2O¡ý+2H2O£»
£¨3£©FΪCH3CH2OH£¬Æäͬ·ÖÒì¹¹ÌåÖ»Óм×ÃÑCH3OCH3£¬¹Ê´ð°¸Îª£ºCH3OCH3£®

µãÆÀ ±¾Ìâͨ¹ýÓлú¿òͼÍƶϿ¼²éÁËõ¥ÀàË®½â¡¢´¼µÄÑõ»¯¡¢ÒÔ¼°Òø¾µ·´Ó¦µÈµÈ֪ʶµã£¬×¢Òâ¾Ý¹ÙÄÜÍŵÄÐÔÖÊÍƶϣ¬ÌâÄ¿ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø