题目内容
(1)若
=
,判断代数式
-
+1值的符号
(2)若
=
=
,求
的值。
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(2)若
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解:(1)设
=
=k,则a=bk,c=dk,代入,得,求值式=
-
+1=k-k+1=1>0,故所求式的符号为正
(2)当a+b+c≠0时,因为abc≠0,所以由等比性质得:
=
=
=
所以a+b=2c,b+c=2a,c+a=2b,代入得,求式=
=8
当a+b+c=0,a+b=--c,b+c=-a,c+a=-b,代入所求式=
=-1
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(2)当a+b+c≠0时,因为abc≠0,所以由等比性质得:
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当a+b+c=0,a+b=--c,b+c=-a,c+a=-b,代入所求式=
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略
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