题目内容
数列{an}满足a1=
|
试题答案
C
相关题目
已知数列{an} 满足:a1=m(m为正整数),an+1=
,若a6=1,则m所有可能的值的集合为( )
|
| A、{4,5} |
| B、{4,32} |
| C、{4,5,32} |
| D、{5,32} |
在数列{an}中,如果对任意的n∈N*,都有
-
=λ(λ为常数),则称数列{an}为比等差数列,λ称为比公差.现给出以下命题,其中所有真命题的序号是
①若数列{Fn}满足F1=1,F2=1,Fn=Fn-1+Fn-2(n≥3),则该数列不是比等差数列;
②若数列{an}满足an=(n-1)•2n-1,则数列{an}是比等差数列,且比公差λ=2;
③等差数列是常数列是成为比等差数列的充分必要条件;
(文)④数列{an}满足:an+1=an2+2an,a1=2,则此数列的通项为an=32n-1-1,且{an}不是比等差数列;
(理)④数列{an}满足:a1=
,且an=
(n≥2,n∈N*),则此数列的通项为an=
,且{an}不是比等差数列.
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| an+2 |
| an+1 |
| an+1 |
| an |
①④
①④
.①若数列{Fn}满足F1=1,F2=1,Fn=Fn-1+Fn-2(n≥3),则该数列不是比等差数列;
②若数列{an}满足an=(n-1)•2n-1,则数列{an}是比等差数列,且比公差λ=2;
③等差数列是常数列是成为比等差数列的充分必要条件;
(文)④数列{an}满足:an+1=an2+2an,a1=2,则此数列的通项为an=32n-1-1,且{an}不是比等差数列;
(理)④数列{an}满足:a1=
| 3 |
| 2 |
| 3nan-1 |
| 2an-1+n-1 |
| n•3n |
| 3n-1 |
设数列{an}的前n项和为 Sn,满足an+Sn=An2+Bn+1(A≠0).
(1)若a1=
,a2=
,求证:数列{an-n}是等比数列,并求数列{an}的通项公式;
(2)已知数列{an}是等差数列,求
的值.
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(1)若a1=
| 3 |
| 2 |
| 9 |
| 4 |
(2)已知数列{an}是等差数列,求
| B-1 |
| A |
(2011•天津模拟)设数列{an} 满足a1=a,an+1=can+1-c(n∈N*),其中a、c为实数,且c≠0.
(1)求数列{an} 的通项公式;
(2)设a=
,c=
,bn=n(a-an)(n∈N*),求数列 {bn}的前n项和Sn.
(3)设a=
,c=-
,cn=
(n∈N*),记dn=c2n-c2n-1(n∈N*),设数列{dn}的前n项和为Tn,求证:对任意正整数n都有Tn<
.
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(1)求数列{an} 的通项公式;
(2)设a=
| 1 |
| 2 |
| 1 |
| 2 |
(3)设a=
| 3 |
| 4 |
| 1 |
| 4 |
| 3+an |
| 2-an |
| 3 |
| 2 |