摘要:设函数f(x)=a-|x|=4,则 B.f C.f>f(2) 答案?A?
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设函数f(x)=1ogax(a>0且a≠1),若f(x1·x2…x2009)=8,则f(x12)+f(x22)+…+f(x22008)+f(x22009)的值等于
[ ]
A.
16
B.
8
C.
4
D.
21oga8
网址:http://m.1010jiajiao.com/timu_id_4207369[举报]
设函数f(x)=1ogax(a>0且a≠1),若f(x1·x2…x2009)=8,则f(x12)+f(x22)+…+f(x22008)+f(x22009)的值等于
16
8
4
21oga8