摘要:16. 或2; 17. .
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计算或解方程:
(1)14-(-12)+(-25)-17
(2)-14-
×[2-(-3)2]
(3)5a2-[3a-(2a-3)+4a2]
(4)3x-4(2x+5)=x+4
(5)
=
+1.
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(1)14-(-12)+(-25)-17
(2)-14-
| 1 |
| 6 |
(3)5a2-[3a-(2a-3)+4a2]
(4)3x-4(2x+5)=x+4
(5)
| x-1 |
| 4 |
| 2x+1 |
| 6 |