摘要:∵CD侧面PCD.AB侧面PCD.∴AB//侧面PCD取CD中点F.连EF.PF.则EF⊥AB又∵PE⊥AB.∴AB⊥平面PEF又∵AB//CD.∴CD⊥平面PEF.∴平面PCD⊥平面PEF-------作EG⊥PF.垂足为G.则EC⊥平面PCD
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(Ⅰ)求证:BE∥平面PAD;
(Ⅱ)求证:BC⊥平面PBD;
(Ⅲ)设Q为侧棱PC上一点,
| PQ |
| PC |
(Ⅰ)求证:BC⊥PB;
(Ⅱ)判断并说明PD上是否存在点G,使得EG∥平面PBC. 查看习题详情和答案>>
| 3 |
(Ⅰ)求证PA⊥CD;
(Ⅱ)求二面角P-AB-D的度数;
(Ⅲ)求证平面PAB⊥平面CDM.