摘要:12.计算2-2+(3.14-)0-|-1|= .
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计算.
(1)-0.52+(-
)2-|-22-4|-(-1
)3×(
)3÷(-
)4
(2){[3
÷(-
)+0.4×(-
)2]÷(-
)-20}×(-1)2005
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(1)-0.52+(-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
(2){[3
| 3 |
| 4 |
| 1 |
| 4 |
| 5 |
| 2 |
| 5 |
| 3 |
计算.
(1)-20+(-14)-(-18)+13
(2)-2+|5-8|-24÷(-3)
(3)(
-
+
)×(-36)
(4)-24+(-3)2+5×(-6)
(5)-14×3-9×(-
)÷
-8×(-
)2.
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(1)-20+(-14)-(-18)+13
(2)-2+|5-8|-24÷(-3)
(3)(
| 5 |
| 9 |
| 3 |
| 4 |
| 1 |
| 18 |
(4)-24+(-3)2+5×(-6)
(5)-14×3-9×(-
| 2 |
| 3 |
| 3 |
| 2 |
| 3 |
| 2 |