ÌâÄ¿ÄÚÈÝ

5£®2015Äê12Ô£¬¹ú¼ÊÑ©Áª×ÔÓÉʽ»¬Ñ©¿ÕÖм¼ÇÉÊÀ½ç±­ÈüÔÚÎÒ¹ú¹ú¼ÒÌåÓý³¡¾ÙÐУ®ÈçͼËùʾ£¬±ÈÈü³¡µØÓɳö·¢ÇøAB¡¢Öú»¬ÆÂBC¡¢µÚÒ»¹ý¶ÉÇøCD¡¢ÌøÌ¨DE¡¢µÚ¶þ¹ý¶ÉÇøEF¡¢×ŽÆÂFGºÍÖÕµãÇøGH×é³É£¬µÚÒ»¹ý¶ÉÇøµÄ×îµÍµãºÍÖÕµãÇøÔÚͬһˮƽµØÃæÉÏ£¬³ö·¢Çø¾àµØÃæµÄ¸ß¶ÈhB=8.4m£¬ÌøÌ¨×î¸ßµãEºÍ׎ÆÂ×î¸ßµãFÀëµØÃæµÄ¸ß¶È¾ùΪh0=4.0m£¬×ŽÆÂÆÂ¶ÈΪ¦È=37¡ã£®Ô˶¯Ô±´ÓÖú»¬ÆÂ¶¥¶ËBÓɾ²Ö¹»¬Ï£¬Àë¿ªÌøÌ¨ÔÚ¿ÕÖÐÍê³ÉÔ¤¶¨¶¯×÷ºóµ½´ïFµãÕýÉÏ·½£¬´ËʱËÙ¶Èv=4.0m/s£¬·½Ïòˮƽ£®ÈôµÚÒ»¹ý¶ÉÇøÊǰ뾶R=42mµÄÔ²»¡»¬µÀ£¬Ô˶¯Ô±Á¬Í¬»¬Ñ©°åµÄ×ÜÖÊÁ¿m=100kg£¬È¡ÖØÁ¦¼ÓËÙ¶Èg=10m/s2£¬²»¼Æ»¬µÀºÍ¿ÕÆøµÄ×èÁ¦£®Çó£º

£¨1£©Ô˶¯Ô±µ½´ïµÚÒ»¹ý¶ÉÇøCDµÄ×îµÍµãʱÊܵ½µÄÖ§³ÖÁ¦FN£»
£¨2£©Ô˶¯Ô±µ½´ïFµãÕýÉÏ·½Ê±ÀëµØÃæµÄ¸ß¶Èh£»
£¨3£©Ô˶¯Ô±Â䵽׎ÆÂʱµÄËÙ¶È´óСv1£®

·ÖÎö £¨1£©¸ù¾Ý»úеÄÜÊØºã¶¨ÂÉ¿ÉÇóµÃ×îµÍµãµÄËÙ¶È£¬ÔÙÓÉÏòÐÄÁ¦¹«Ê½¿ÉÇóµÃÖ§³ÖÁ¦´óС£»
£¨2£©¸ù¾Ý»úеÄÜÊØºã¶¨ÂÉ¿ÉÇóµÃÔ˶¯Ô±µ½´ïFµãÕýÖ¹·½Ê±ÀëµØ¸ß¶È£»
£¨3£©¸ù¾ÝƽÅ×Ô˶¯µÄ¹æÂÉ¿ÉÇóµÃÔ˶¯Ô±Â䵽׎ÆÂÉϵÄËÙ¶È´óС£®

½â´ð ½â£º£¨1£©ÉèÔ˶¯Ô±µ½´ïµÚÒ»¹ý¶ÉÇøCD×îµÍµãʱËÙ¶È´óСΪv0£¬Ôò
ÓÉ»úеÄÜÊØºã¶¨ÂÉ¿ÉÖª£º
$mg{h_B}=\frac{1}{2}mv_0^2$
¸ù¾ÝÏòÐÄÁ¦¹«Ê½¿ÉÖª
${F_N}-mg=m\frac{v_0^2}{R}$
½âµÃFN=1400N£» 
£¨2£©Ô˶¯Ô±´ÓBµã³ö·¢µ½´ïFµãÕýÉÏ·½µÄ¹ý³ÌÖÐ$mg£¨{h_B}-h£©=\frac{1}{2}m{v^2}$
½âµÃ  h=7.6m
£¨3£©ÉèÔ˶¯Ô±´Ó¿ÕÖÐ×î¸ßµãÂ䵽׎ÆÂ¾­¹ýµÄʱ¼äΪt£¬Ë®Æ½Î»ÒÆÎªx£¬Ôòx=vt
$h-£¨{h_0}-xtan37¡ã£©=\frac{1}{2}g{t^2}$
½âµÃ  t=1.2s
Ô˶¯Ô±Â䵽׎ÆÂÉϵÄËÙ¶È´óС${v_1}=\sqrt{{v^2}+{{£¨gt£©}^2}}=4\sqrt{10}m/s$
´ð£º£¨1£©Ô˶¯Ô±µ½´ïµÚÒ»¹ý¶ÉÇøCDµÄ×îµÍµãʱÊܵ½µÄÖ§³ÖÁ¦FNΪ1400N£»
£¨2£©Ô˶¯Ô±µ½´ïFµãÕýÉÏ·½Ê±ÀëµØÃæµÄ¸ß¶ÈhΪ7.6m£»
£¨3£©Ô˶¯Ô±Â䵽׎ÆÂʱµÄËÙ¶È´óСv1Ϊ4$\sqrt{10}$m/s£®

µãÆÀ ±¾Ì⿼²éÁË»úеÄÜÊØºã¡¢ÏòÐÄÁ¦ÒÔ¼°Æ½Å×Ô˶¯µÄ¹æÂÉ£¬Òª×¢ÒâÃ÷È·ÎïÌåµÄÔ˶¯¹ý³Ì£¬¸ù¾ÝÊÜÁ¦·ÖÎöÁé»îÑ¡ÔñÎïÀí¹æÂÉÇó½â¼´¿É£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
15£®Ì½¾¿¡°¹¦ÓëÎïÌåËٶȱ仯¹ØÏµ¡±µÄʵÑéÈçͼ1£¬Í¼ÖÐС³µÊÇÔÚÒ»ÌõÏðÆ¤½î×÷ÓÃϵ¯³ö£¬ÑØÄ¾°å»¬ÐУ¬Õâʱ£¬ÏðÆ¤½î¶ÔС³µ×öµÄ¹¦¼ÇΪW£®µ±ÓÃ2Ìõ¡¢3Ìõ¡­ÍêÈ«ÏàͬµÄÏðÆ¤½î²¢ÔÚÒ»Æð½øÐеÚ2´Î¡¢µÚ3´Î¡­ÊµÑéʱ£¬Ê¹Ã¿´ÎʵÑéÖÐÏðÆ¤½îÉ쳤µÄ³¤¶È¶¼±£³ÖÒ»Ö£®Ã¿´ÎʵÑéÖÐС³µ»ñµÃµÄËÙ¶ÈÓÉ´òµã¼ÆÊ±Æ÷Ëù´òµÄÖ½´ø²â³ö£®
£¨1£©³ýÁËͼÖÐÒÑÓеÄʵÑéÆ÷²ÄÍ⣬»¹ÐèÒªµ¼Ïß¡¢¿ª¹Ø¡¢¿Ì¶È³ßºÍ½»Á÷µçÔ´£¨Ìî¡°½»Á÷¡±»ò¡°Ö±Á÷¡±£©£®ÔÚ¸Ã×°ÖÃÖУ¬Ó°ÏìС³µÔ˶¯µÄ×èÁ¦ÓÐľ°åºÍС³µ¼äµÄĦ²Á×èÁ¦£®ÎªÁËÆ½ºâÕâЩ×èÁ¦µÄÓ°Ï죬¿ÉÒÔÊʵ±µæ¸ßľ°åµÄ×ó£¨Ìî¡°×ó¡±»ò¡°ÓÒ¡±£©¶Ë£¬Ê¹Ä¾°åÂÔ΢Çãб£®
£¨2£©ÊµÑéÖУ¬Ð¡³µ»áÊܵ½Ä¦²Á×èÁ¦µÄ×÷Ó㬿ÉÒÔʹľ°åÊʵ±ÇãбÀ´Æ½ºâĦ²Á×èÁ¦£¬ÔòÏÂÃæ²Ù×÷ÕýÈ·µÄÊÇD£®
A£®ÇáÍÆÐ¡³µ£¬Äܹ»ÔÈËÙÏ»¬¼´¿É      B£®·Å¿ªÐ¡³µ£¬Ð¡³µÄܹ»Ï»¬¼´¿É
C£®·Å¿ªÍÏ×ÅÖ½´øµÄС³µ£¬Äܹ»Ï»¬¼´¿ÉD£®ÇáÍÆÒ»ÏÂÍÏ×ÅÖ½´øµÄС³µ£¬Äܹ»ÔÈËÙÏ»¬
£¨3£©Èôľ°åˮƽ·ÅÖã¬Ð¡³µÔÚÁ½ÌõÏðÆ¤½î×÷ÓÃÏÂÔ˶¯£¬µ±Ð¡³µËÙ¶È×î´óʱ£¬¹ØÓÚÏðÆ¤½îËù´¦µÄ״̬ÓëС³µËùÔÚµÄλÖã¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇB£®

A£®ÏðÆ¤½î´¦ÓÚÔ­³¤×´Ì¬
B£®ÏðÆ¤½îÈÔ´¦ÓÚÉ쳤״̬
C£®Ð¡³µÔÚÁ½¸öÌú¶¤µÄÁ¬Ïß´¦
D£®Ð¡³µÒѹýÁ½¸öÌú¶¤µÄÁ¬Ïß
£¨4£©ÔÚÕýÈ·²Ù×÷Çé¿öÏ£¬´òÔÚÖ½´øÉϵĵ㲢²»¶¼ÊǾùÔȵģ¬ÎªÁ˲âÁ¿Ð¡³µ»ñµÃµÄËÙ¶È£¬Ó¦Ñ¡ÓÃͼ2Ö½´øµÄFJ²¿·Ö½øÐвâÁ¿£¨ÓÃÖ½´øÉϵÄ×Öĸ±íʾ£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø