ÌâÄ¿ÄÚÈÝ

20£®2015Äê9ÔÂ14ÈÕ£¬ÃÀ¹úµÄLIGO̽²âÉèÊ©½ÓÊÕµ½Ò»¸öÀ´×ÔGW 150914µÄÒýÁ¦²¨Ðźţ¬´ËÐźÅÊÇÓÉÁ½¸öºÚ¶´µÄºÏ²¢¹ý³Ì²úÉúµÄ£®Èç¹û½«Ä³¸öË«ºÚ¶´ÏµÍ³¼ò»¯ÎªÈçͼËùʾµÄÔ²ÖÜÔ˶¯Ä£ÐÍ£¬Á½ºÚ¶´ÈÆOµã×öÔÈËÙÔ²ÖÜÔ˶¯£®ÔÚÏ໥ǿ´óµÄÒýÁ¦×÷ÓÃÏ£¬Á½ºÚ¶´¼äµÄ¾àÀëÖð½¥¼õС£¬Ôڴ˹ý³ÌÖУ¬Á½ºÚ¶´×öÔ²ÖÜÔ˶¯µÄ£¨¡¡¡¡£©
A£®ÖÜÆÚ¾ùÖð½¥Ôö´óB£®ÏßËٶȾùÖð½¥¼õС
C£®½ÇËٶȾùÖð½¥Ôö´óD£®ÏòÐļÓËٶȾùÖð½¥¼õС

·ÖÎö Ë«ÐÇ×öÔÈËÙÔ²ÖÜÔ˶¯¾ßÓÐÏàͬµÄ½ÇËÙ¶È£¬¿¿Ï໥¼äµÄÍòÓÐÒýÁ¦ÌṩÏòÐÄÁ¦£¬¸ù¾ÝÍòÓÐÒýÁ¦ÌṩÏòÐÄÁ¦µÃ³öË«ÐǵĹìµÀ°ë¾¶¹ØÏµ£¬´Ó¶øÈ·¶¨³öË«Ðǵİ뾶ÈçºÎ±ä»¯£¬ÒÔ¼°µÃ³öË«ÐǵĽÇËÙ¶È¡¢ÏßËÙ¶È¡¢¼ÓËٶȺÍÖÜÆÚµÄ±ä»¯£®

½â´ð ½â£ºA¡¢¸ù¾Ý$G\frac{{M}_{1}{M}_{2}}{{L}^{2}}$=${M}_{1}\frac{4{¦Ð}^{2}{R}_{1}}{{T}^{2}}$£¬½âµÃ${M}_{2}=\frac{4{¦Ð}^{2}{R}_{1}}{{GT}^{2}}$L2
ͬÀí¿ÉµÃ${M}_{1}=\frac{4{¦Ð}^{2}{L}^{2}}{G{T}^{2}}$R2
ËùÒÔ${M}_{1}+{M}_{2}=\frac{4{¦Ð}^{2}{L}^{2}}{G{T}^{2}}£¨{R}_{1}+{R}_{2}£©=\frac{4{¦Ð}^{2}{L}^{3}}{G{T}^{2}}$
µ±M1+M2²»±äʱ£¬LÔö´ó£¬ÔòTÔö´ó£¬¼´Ë«ÐÇϵͳÔËÐÐÖÜÆÚ»áËæ¼ä¾à¼õС¶ø¼õС£¬¹ÊA´íÎó£»
B¡¢¸ù¾Ý$G\frac{{M}_{1}{M}_{2}}{{L}^{2}}=\frac{{{M}_{1}v}_{1}^{2}}{2{R}_{1}}$£¬½âµÃ${v}_{1}=\sqrt{\frac{G{M}_{2}{R}_{1}}{{L}^{2}}}$£¬ÓÉÓÚLƽ·½µÄ¼õС±Èr1ºÍr2µÄ¼õСÁ¿´ó£¬ÔòÏßËÙ¶ÈÔö´ó£¬¹ÊB´íÎó£®
C¡¢½ÇËÙ¶È$¦Ø=\frac{2¦Ð}{T}$£¬½áºÏA¿ÉÖª£¬½ÇËÙ¶ÈÔö´ó£¬¹ÊCÕýÈ·£»
D¡¢¸ù¾Ý$G\frac{{M}_{1}{M}_{2}}{{L}^{2}}$=M1a1=M2aÖª£¬L±äС£¬ÔòÁ½ÐǵÄÏòÐļÓËÙ¶ÈÔö´ó£¬¹ÊD´íÎó£®
¹ÊÑ¡£ºC

µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÖªµÀË«ÐÇ¿¿Ï໥¼äµÄÍòÓÐÒýÁ¦ÌṩÏòÐÄÁ¦£¬ÖªµÀË«ÐǵĹìµÀ°ë¾¶±ÈµÈÓÚÖÊÁ¿Ö®·´±È

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
15£®ÈçͼËùʾ£¬ÓÐÒ»¹Ì¶¨ÔÚË®Æ½ÃæµÄƽֱ¹ìµÀ£¬¸Ã¹ìµÀÓɰ×É«¹ìµÀºÍºÚÉ«¹ìµÀ½»ÌæÅÅÁв¢Æ½»¬Á¬½Ó¶ø³É£®¸÷¶Î¹ìµÀµÄ±àºÅÒÑÔÚͼÖбê³ö£®½öºÚÉ«¹ìµÀ´¦ÔÚÊúÖ±ÏòÉϵÄÔÈÇ¿µç³¡ÖУ¬Ò»²»´øµçµÄС»¬¿éA¾²Ö¹ÔÚµÚ1¶Î¹ìµÀµÄ×î×ó¶Ë£¬¾øÔµ´øµçС»¬¿éB¾²Ö¹ÔÚµÚ1¶Î¹ìµÀµÄ×îÓÒ¶Ë£®Ä³Ê±¿Ì¸øÐ¡»¬¿éAÊ©¼ÓһˮƽÏòÓҵĺãÁ¦F£¬Ê¹Æä´Ó¾²Ö¹¿ªÊ¼ÑعìµÀÏòÓÒÔ˶¯£¬Ð¡»¬¿éAÔ˶¯µ½ÓëС»¬¿éBÅöײǰ˲¼ä³·È¥Ð¡»¬¿éAËùÊÜˮƽºãÁ¦£®»¬¿éA¡¢BÅöײʱ¼ä¼«¶Ì£¬ÅöºóÕ³ÔÚÒ»ÆðÑØ¹ìµÀÏòÓÒÔ˶¯£®ÒÑÖª°×É«¹ìµÀºÍºÚÉ«¹ìµÀ¸÷¶ÎµÄ³¤¶È¾ùΪL=0.10m£¬ÔÈÇ¿µç³¡µÄµç³¡Ç¿¶ÈµÄ´óСE=1.0¡Á104N/C£»»¬¿éA¡¢BµÄÖÊÁ¿¾ùΪm=0.010kg£¬»¬¿éA¡¢BÓë¹ìµÀ¼äµÄ¶¯Ä¦²ÁÒòÊý´¦´¦ÏàµÈ£¬¾ùΪ¦Ì=0.40£¬¾øÔµ»¬¿éBËù´øµçºÉÁ¿q=+1.0¡Á10-5C£¬Ð¡»¬¿éAÓëС»¬¿éBÅöײǰ˲¼äµÄËÙ¶È´óСv=6.0m/s£®A¡¢B¾ù¿ÉÊÓΪÖʵ㣨ºöÂÔËüÃǵijߴç´óС£©£¬ÇÒ²»¼ÆA¡¢B¼äµÄ¾²µçÁ¦×÷£®ÔÚA¡¢BÕ³ÔÚÒ»ÆðÑØ¹ìµÀÏòÓÒÔ˶¯¹ý³ÌÖеçºÉÁ¿±£³Ö²»±ä£¬È¡ÖØÁ¦¼ÓËÙ¶Èg=10m/s2£® 

£¨1£©ÇóFµÄ´óС£»
£¨2£©Åöײ¹ý³ÌÖл¬¿éB¶Ô»¬¿éAµÄ³åÁ¿£»
£¨3£©ÈôAºÍB×îÖÕÍ£ÔÚ¹ìµÀÉϱàºÅΪkµÄÒ»¶Î£¬ÇókµÄÊýÖµ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø