2.已知e为自然对数的底数,若对任意的x∈[$\frac{1}{e}$,1],总存在唯一的y∈[-1,1],使得lnx-x+1+a=y2ey成立,则实数a的取值范围是( )
0 226842 226850 226856 226860 226866 226868 226872 226878 226880 226886 226892 226896 226898 226902 226908 226910 226916 226920 226922 226926 226928 226932 226934 226936 226937 226938 226940 226941 226942 226944 226946 226950 226952 226956 226958 226962 226968 226970 226976 226980 226982 226986 226992 226998 227000 227006 227010 227012 227018 227022 227028 227036 266669
| A. | [$\frac{1}{e}$,e] | B. | ($\frac{2}{e}$,e] | C. | ($\frac{2}{e}$,+∞) | D. | ($\frac{2}{e}$,e+$\frac{1}{e}$) |