题目内容

已知|
OA
|=1,|
OB
|=
3
OA
OB
=0,点C在∠AOB内,且∠AOC=30°,设
OC
=m
OA
+n
OB
(m、n∈R),则
m
n
等于______.
∵|
OA
|=1,|
OB
|=
3
OA
OB
=0,
OA
OB

OC
OB
=OC×
3
cos60°
=
3
2
OC
=
3
×
1
2
 |OC |

OC
OA
=|OC|×1×cos30°=
3
2
|OC|
=1×
3
2
|OC|

OC
在x轴方向上的分量为
1
2
|OC|

OC
在y轴方向上的分量为
3
2
|OC|

OC
=m
OA
+n
OB
=
3
n
i
+m
j

1
2
|OC|=
3
n
3
2
|OC|=m

两式相比可得:
m
n
=3.
故答案为:3
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